CHEMISTRY, M2 EQ-Bank 8 MC

A student prepares a standard solution of sodium chloride. They dissolve 5.85 g of sodium chloride \(\ce{(NaCl)}\) in enough water to make 1.00 L of solution. Determine the concentration of this solution?

0.100 mol L\(^{-1}\)
0.500 mol L\(^{-1}\)
1.00 mol L\(^{-1}\)
5.85 mol L\(^{-1}\)

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\(A\)

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\(n\ce{(NaCl)} = \dfrac{5.85}{22.99 + 35.45} = 0.100\ \text{mol}\)

\(\ce{[NaCl]} = \dfrac{n}{V} = \dfrac{0.100}{1} = 0.100\ \text{mol L}^{-1}\)

\(\Rightarrow A\)