Consider the function \(y=f(x)\) where
\(f(x)= \begin{cases}x^2+6, & \text { for } x \leqslant 0 \\ 6, & \text { for } 0<x \leqslant 3 \\ 2^x, & \text { for } x>3\end{cases}\)
- Sketch \(y=f(x)\) (3 marks)
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- For what value of \(x\) is \(y=f(x)\) NOT continuous? (1 mark)
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