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Functions, 2ADV EQ-Bank 5

  1. Identify where the graph  \(f(x)=\dfrac{x^2-1}{x-1}\)  is not continuous.   (1 mark)

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  2. Sketch the graph of \(f(x)\).   (2 marks)

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Show Answers Only

a.    \(f(x)=\dfrac{x^2-1}{x-1}=\dfrac{(x+1)(x-1)}{(x-1)}=x+1\)

\(\text{Since denominator} \neq 0\)

\(f(x) \ \ \text{is not continuous when} \ \ x=1.\)
 

b.
       

Show Worked Solution

a.    \(f(x)=\dfrac{x^2-1}{x-1}=\dfrac{(x+1)(x-1)}{(x-1)}=x+1\)

\(\text{Since denominator} \neq 0\)

\(f(x) \ \ \text{is not continuous when} \ \ x=1.\)
 

b.
       

Filed Under: Piecewise Functions (Adv-2027) Tagged With: Band 3, Band 4, smc-6217-10-Sketch graph, smc-6217-40-Continuity, syllabus-2027

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