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Algebraic Techniques, SM-Bank 138

Use the rectangle below to prove that \((a+b)^2=a^2+2ab+b^2\).   (3 marks)
 

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\(\text{Length of large rectangle}\) \(=a+b\)
\(\text{Width of large rectangle}\) \(=a+b\)

 

\(\text{Area of large rectangle}\) \(=(a+b)\times(a+b)\)
  \(=(a+b)^2\)

 

\(\text{Adding 4 areas inside large rectangle}\) \(=a^2+a\times b+a\times b+b^2\)
  \(=a^2+2ab+b^2\)

 

\(\therefore (a+b)^2=a^2+2ab+b^2\)

Filed Under: Expand and Factorise Tagged With: num-title-ct-core, smc-4696-10-Expand

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