Algebraic Techniques, SM-Bank 138 Use the rectangle below to prove that \((a+b)^2=a^2+2ab+b^2\). (3 marks) --- 5 WORK AREA LINES (style=lined) --- Show Answers Only \(\text{See worked solution}\) Show Worked Solution \(\text{Length of large rectangle}\) \(=a+b\) \(\text{Width of large rectangle}\) \(=a+b\) \(\text{Area of large rectangle}\) \(=(a+b)\times(a+b)\) \(=(a+b)^2\) \(\text{Adding 4 areas inside large rectangle}\) \(=a^2+a\times b+a\times b+b^2\) \(=a^2+2ab+b^2\) \(\therefore (a+b)^2=a^2+2ab+b^2\)