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Algebraic Techniques, SM-Bank 145

State the highest common factor of \(15xy\ \text{and}\ 20y\).  (1 mark)

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\(5y\)

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\(\text{HCF of}\ 15\ \text{and}\ 20=5\)

\(\text{HCF of}\ xy\ \text{and}\ y=y\)

\(\therefore\ \text{HCF of}\ 15xy\ \text{and}\ 20y=5y\)

Filed Under: Expand and Factorise Tagged With: num-title-ct-core, smc-4696-20-Factorise

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