Algebraic Techniques, SM-Bank 152 A rectangle has an area of \(9a^2-6a\). By factorising the expression, find the width of the rectangle if the length is \(3a\). (2 marks) Show Answers Only \(3a-2\) Show Worked Solution \(9a^2-6a\) \(=3a\times 3a+3a\times (-2)\ \ \ \ (\text{HCF}=3a)\) \(=3a(3a-2)\) \(\therefore\ \text{Width of rectangle}=3a-2\)