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Area, SM-Bank 041

A golf course has a sprinkler system that waters the grass in the shape of a sector, as shown in the diagram below. 
 

A sprinkler is positioned at point \(L\) and can turn through an angle of 100°.

The section of grass that is watered is 4.5 m wide at all points.

Water can reach a maximum of 12 m from the sprinkler at \(L\).

What is the area of grass that this sprinkler will water?

Round your answer to the nearest square metre.  (2 marks)

NOTE:  \(\text{Sector Area}=\dfrac{\theta}{360}\times \pi r^2\)

--- 4 WORK AREA LINES (style=lined) ---

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`199\ text{m²  (nearest m²)}`

Show Worked Solution
\(\text{Area}\) \(=\dfrac{360-\theta}{360}\times \pi\times R^2-\dfrac{360-\theta}{360}\times \pi\times r^2\)
  \(=\dfrac{260}{360}\times \pi\times 12^2-\dfrac{260}{360}\times \pi\times 7.5^2\)
  \(= 199.09\dots\)
  \(= 199\ \text{m²  (nearest m}^2)\)

 

Filed Under: Circular measure Tagged With: num-title-ct-core, smc-4944-30-Sectors

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