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Area, SM-Bank 060

The parallelogram below has an area of 75.03 square centimetres and a base length of 12.3 centimetres.

Calculate the perpendicular height of the parallelogram.  (2 marks)

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\(6.1\ \text{cm}\)

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\(\text{Area}\) \(=\text{base}\times \text{height}\)
\(\therefore\ 75.03\) \(=12.3\times h\)
\(h\) \(=\dfrac{75.03}{12.3}\)
  \(=6.1\)

 
\(\therefore\ \text{The perpendicular height of the parallelogram is }6.1\ \text{cm.}\)

Filed Under: Quadrilaterals Tagged With: num-title-ct-core, smc-4943-20-Parallelograms

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