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Area, SM-Bank 134

A kite has an area of \(32\ 240\) square centimetres. Given that one of the diagonals has a length of 124 centimetres, calculate the length of the other diagonal.  (2 marks)

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\(520\ \text{cm}\)

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\(\text{Let the unknown diagonal}=x\)

\(A\) \(=\dfrac{1}{2}xy\)
\(32\ 240\) \(=\dfrac{1}{2}\times 124\times x\)
\(62x\) \(=32\ 240\)
\(x\) \(=\dfrac{32\ 240}{62}\)
  \(=520\ \text{cm}\)

Filed Under: Quadrilaterals Tagged With: num-title-ct-core, smc-4943-50-Rhombuses and kites

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