SmarterEd

Aussie Maths & Science Teachers: Save your time with SmarterEd

  • Login
  • Get Help
  • About

v1 Algebra, STD2 A4 2021 HSC 35

A toy store releases a limited edition LEGO set for $20 each. At this price, 3000 LEGO sets are sold each week and the revenue is  `3000 xx 20=$60\ 000`.

The toy store considers increasing the price. For every dollar price increase, 15 fewer LEGO sets will be sold.

If the toy store charges `(20+x)` dollars for each LEGO set, a quadratic model for the revenue raised, `R`, from selling them is

`R=-15x^2+2700x+60\ 000`

 


 

  1. What price should be charged per LEGO set to maximise the revenue?   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. How many LEGO sets are sold when the revenue is maximised?   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  3. Find the value of the intercept of the parabola with the vertical axis.   (1 mark) 

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.   `$110`

b.    `1650`

c.   `$60\ 000`

Show Worked Solution

a.   `text{Highest revenue}\ (R_text{max})\ text(occurs halfway between)\ \ x= -20 and x=200.`

`text{Midpoint}\ =(-20 + 200)/2 = 90`

`:.\ text(Price of LEGO set for)\ R_text(max)`

`=90 + 20`

`=$110`
 

b.  `text{LEGO sets sold when}\ R_{max}`

`=3000-(90 xx 15)`

`=1650`
 

c.   `ytext(-intercept → find)\ R\ text(when)\ \ x=0:`

`R` `= -15(0)^2 + 2700(0) + 60\ 000`
  `=$60\ 000`

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 5, Band 6, smc-830-20-Quadratics

v1 Algebra, STD2 A4 2017 HSC 28e

Sage brings 60 cartons of unpasteurised milk to the market each week. Each carton currently sells for $4 and at this price, all 60 cartons are sold each weekend.

Sage considers increasing the price to see if the total income can be increased.

It is assumed that for each $1 increase in price, 6 fewer cartons will be sold.

A graph showing the relationship between the increase in price per carton and the income is shown below.

 


 

  1. What price per carton should be charged to maximise the income?   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. What is the number of cartons sold when the income is maximised?   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  3. The cost of running the market stall is $40 plus $1.50 per carton sold.

    Calculate Sage's profit when the income earned from a day selling at the market is maximised.   (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

a.   `$7`

b.   `42`

c.   `$191`

Show Worked Solution

a.   `text(Graph is highest when increase = $3)`

`:.\ text(Carton price)\ = 4 + 3= $7`
 

b.   `text(Cartons sold)\ =60-(3 xx 6)=42`
  

c.   `text{Cost}\ = 42 xx 1.50 + 40 = $103`

`:.\ text(Profit when income is maximised)`

`= (42 xx 7)-103`

`= $191`

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 4, Band 5, num-title-ct-coreb, num-title-qs-hsc, smc-4443-70-Other applications, smc-830-20-Quadratics

v1 Algebra, STD2 A4 2009 HSC 28c

The brightness of a lamp \((L)\) is measured in lumens and varies directly with the square of the voltage \((V)\) applied, which is measured in volts.

When the lamp runs at 7 volts, it produces 735 lumens.

What voltage is required for the lamp to produce 1820 lumens? Give your answer correct to one decimal place.   (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

Show Answers Only

 `11.2\ \text(volts)`

Show Worked Solution
♦♦ Mean mark 22%
TIP: Establishing `L=k V^2` is the key part of solving this question.

`L prop V^2\ \ => \ \ L=kV^2`

`text(Find)\ k\ \text{given}\ L = 735\ \text{when}\ V = 7:`

`735` `= k xx 7^2`
`:. k` `= 735/49=15`

 
`text(Find)\ V\ text(when)\ L = 1820:`

`1820` `= 15 xx V^2`
`V^2` `= 1820/15=121.33…`
`V` `= sqrt{121.33} = 11.2\ text(volts)\ \ text{(to 1 d.p.)}`

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 5, num-title-ct-patha, num-title-qs-hsc, smc-4239-40-a prop other, smc-830-20-Quadratics, smc-830-60-Proportional

v1 Algebra, STD2 A4 2021 HSC 24

A population of Tasmanian devils, `D`, is to be modelled using the function  `D = 650 (0.8)^t`, where `t` is the time in years.

  1. What is the initial population?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. Find the population after 2 years.   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. On the axes below, draw the graph of the population against time, in the period  `t = 0`  to  `t = 6`.   (2 marks)
      

    --- 0 WORK AREA LINES (style=lined) ---

Show Answers Only

a.   `650`

b.   `416`

c.   `text{See Worked Solutions}`

Show Worked Solution

a.   `text{Initial population occurs when}\ \  t = 0:`

`D=650(0.8)^0=650 xx 1= 650`
 

b.    `text{Find} \ D \ text{when} \ \ t = 5: `

`D= 650 (0.8)^2= 416`

♦ Mean mark (c) 48%.

 
c. 
 `\text{At}\ t=6:`

`D=650(0.8)^6=170.39…`
 

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 3, Band 4, Band 5, num-title-ct-coreb, num-title-qs-hsc, smc-4444-40-Population, smc-830-30-Exponential

v1 Algebra, STD2 A4 EO-Bank 1

Taylor discovers that for a Spotted stingray, its mass is directly proportional to the square of its wingspan.

One Spotted stingray has a wingspan of 60 cm and a mass of 5400 grams.

What is the expected wingspan of a Spotted stingray with a mass of 9.6 kg?   (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

Show Answers Only

`80.0\ text{cm}`

Show Worked Solution

`text(Mass) prop text(wingspan)^2\ \ =>\ \ m = kw^2`

`text(Find)\ k:`

`5400` `= k xx 60^2`
`k` `= 5400/60^2= 1.5`

 
`text(Find)\ w\ text(when)\ \ m = 9600:`

`9600` `= 1.5 xx w^2`
`w^2` `= 9600/1.5=6400`
`:. w` `= 80\ text{cm}`

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 4, smc-830-20-Quadratics, smc-830-60-Proportional

v1 Algebra, STD2 A4 2023 HSC 22

The stopping distance of a motor bike, in metres, is directly proportional to the square of its speed in km/h, and can be represented by the equation

`text{stopping distance}\ = k xx text{(speed)}^2`

where `k` is the constant of variation.

The stopping distance for a motor bike travelling at 40 km/h is 16 m.

  1. Find the value of `k`.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. What is the stopping distance when the speed of the motor bike is 80 km/h?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `k=0.01`

b.    `64.0\ text{m}`

Show Worked Solution

a.  `text{stopping distance}\ = k xx text{(speed)}^2`

`16` `=k xx 40^2`  
`k` `=16/40^2=0.001`  

 
b.    `text{Find stopping distance}\ (d)\ text{when speed = 80 km/h:}`

`d=0.01 xx 80^2=64.0\ text{m}`

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 4, smc-830-20-Quadratics, smc-830-60-Proportional

v1 Algebra, STD2 A4 2013 HSC 22 MC

Jevin wants to build a rectangular chicken pen. He has 32 metres of fencing and will use a barn wall as one side of the pen. The width of the pen is \(d\) metres.
 

Which equation gives the area, \(P\), of the chicken pen?

  1. \(P = 16d-d^2\)
  2. \(P = 32d-d^2\)
  3. \(P = 16d-\dfrac{d^2}{2}\)
  4. \(P = 16d-2d^2\) 
Show Answers Only

\(C\)

Show Worked Solution
♦♦♦ Mean mark 24% (lowest mean of any MC question in 2013 exam)

\(\text{Length of pen}\ = \dfrac{1}{2}(32-d)\)

\(\text{Area}\ =d \times \dfrac{1}{2}(32-d)=16d-\dfrac{d^2}{2}\)

 \(\Rightarrow C\)

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 6, smc-830-20-Quadratics

v1 Algebra, STD2 A4 2021 HSC 10 MC

Which of the following best represents the graph of  \(y = 5 (0.4)^{x}\) ?
 

Show Answers Only

\(D\)

Show Worked Solution

\(\text{By elimination:}\)

♦ Mean mark 41%.

\(\text{When}\  x = 0, \ y = 5 \times (0.4)^0 = 5\)

\(\rightarrow\ \text{Eliminate B and C} \)

\(\text{As}\ \ x \rightarrow \infty, \ y \rightarrow 0 \)

\(\rightarrow\ \text{Eliminate A} \)

\(\Rightarrow D\)

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: 2adv-std2-common, Band 5, common-content, num-title-ct-coreb, num-title-qs-hsc, smc-4444-10-Identify graphs, smc-830-10-Identify Graphs, smc-830-30-Exponential

v1 Algebra, STD2 A4 2008 HSC 4 MC

Which graph best represents  \(y = \dfrac{2}{x}\) ?
 

Show Answers Only

\(B\)

Show Worked Solution

\(y = \dfrac{2}{x}\ \text{does not touch either axis (inverse graph)}.\)

\(\Rightarrow B\)

Filed Under: Exponential/Quadratic (Projectile), Exponentials, Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 4, num-title-ct-corea, num-title-qs-hsc, smc-4444-10-Identify graphs, smc-830-10-Identify Graphs

v1 Algebra, STD2 A4 2022 HSC 9 MC

An object is projected vertically into the air. Its height, \(h\) metres, above the ground after \(t\) seconds is given by  \(h=-5 t^2+80 t\).
 

How far does the object travel in the first 10 seconds?

  1. 300 metres
  2. 320 metres
  3. 340 metres
  4. 480 metres
Show Answers Only

\(C\)

Show Worked Solution

\(\text{By symmetry (or graph), object reaches max height at}\ \ t=8\ \text{seconds.}\)

\(\text{Find}\ h\ \text{when}\ \ t=8:\)

\(h=-5 \times 8^2-10 \times 8= 320 \)

\(\text{When}\ \ t=10\ \ \Rightarrow\ \ h=300\ \text{(from graph)}\)

\(\therefore\ \text{Total distance}\ = 320 + 20=340\ \text{metres}\)

\(\Rightarrow C\)

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 5, num-title-ct-coreb, num-title-qs-hsc, smc-4443-60-Projectiles, smc-830-20-Quadratics

v1 Algebra, STD2 A4 2018 HSC 4 MC

Which graph best represents the equation  \(y = 2-x^2\) ?
 

A. B.
C. D.
Show Answers Only

\(D\)

Show Worked Solution

\(y = 2-x^2\)

\(y\text{-intercept}\ = -2\ \ \text{(when}\ x = 0)\)

\(\text{Quadratic is concave down (sad) with vertex at}\ (0,2). \)

\(\Rightarrow A\)

Filed Under: Non-Linear: Exponential/Quadratics (Std 2-X) Tagged With: Band 3, num-title-ct-corea, num-title-qs-hsc, smc-4443-10-Identify graphs, smc-830-10-Identify Graphs

Copyright © 2014–2025 SmarterEd.com.au · Log in