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Measurement, STD2 EQ-Bank 04 MC

Kathmandu is  30\(^{\circ}\) west of Perth. Using longitudinal distance, what is the time in Kathmandu when it is noon in Perth?

  1. 10:00 am
  2. 11:30 am
  3. 12:30 pm
  4. 2:00 pm
Show Answers Only

\(A\)

Show Worked Solution

\(15^{\circ}\ =\text{1 hour time difference}\)

\(\text{Longitudinal distance}\) \(=30^{\circ}\)
\(\therefore\ \text{Time Difference}\) \(=\dfrac{30}{15}\)
  \(=2\ \text{hours}\)

  
\(\text{Time in Perth}\ =\ 12\ \text{pm}\)

\(\therefore\ \text{Time in Kathmandu}\) \( =\ 12\ \text{pm}\ -\ 2\ \text{hours}\)
  \(=\ 10:00\ \text{am}\)

\(\Rightarrow A\)

Filed Under: Positions on the Earth's Surface (Std2-2027), Time and Time Difference (Std2-2027) Tagged With: Band 4, smc-6305-10-Longitude and Time Differences, smc-6306-10-Time Differences, syllabus-2027

Measurement, STD2 EQ-Bank 03

The table shows the approximate coordinates of two cities.

\begin{array} {|l|c|c|}
\hline
\rule{0pt}{2.5ex} \textit{City} \rule[-1ex]{0pt}{0pt} & \textit{Latitude} \rule[-1ex]{0pt}{0pt} & \textit{Longitude}\\
\hline
\rule{0pt}{2.5ex} \text{Buenos Aires} \rule[-1ex]{0pt}{0pt} & 35^{\circ}\ \text{S} \rule[-1ex]{0pt}{0pt} & 60^{\circ}\ \text{W}  \\
\hline
\rule{0pt}{2.5ex} \text{Adelaide} \rule[-1ex]{0pt}{0pt} & 35^{\circ}\ \text{S}  \rule[-1ex]{0pt}{0pt} & 140^{\circ}\ \text{E}  \\
\hline
\end{array}

  1. What is the time difference between Adelaide and Buenos Aires?   (2 marks)
  2. --- 4 WORK AREA LINES (style=lined) ---

  3. Roy lives in Adelaide and his cousin Juan lives in Buenos Aires. Roy wants to telephone Juan at 7 pm on Friday night, Buenos Aires time.
  4. At what time, and on what day, should Roy make the call?   (2 marks)
  5. --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(13\ \text{hours}\ 20\ \text{minutes}\)

b.    \(8:20\ \text{am on Saturday}\)

Show Worked Solution

a.    \(15^{\circ}\ =\text{1 hour time difference}\)

\(\text{Angular distance}\) \(=60+140=200^{\circ}\)
\(\therefore\ \text{Time Difference}\) \(=\dfrac{200}{15}\)
  \(=13.\dot{3}\)
  \(=13\ \text{hours}\ 20\ \text{minutes}\)

  
b.    
\(\text{Time in Buenos Aires}\ =\ 7\ \text{pm Friday night}\)

\(\therefore\ \text{Time in Adelaide}\) \( =\ 7\ \text{pm}\ +\ 13\ \text{hours}\ 20\ \text{minutes}\)
  \(=\ 8:20\ \text{am on Saturday}\)
   

Filed Under: Positions on the Earth's Surface (Std2-2027), Time and Time Difference (Std2-2027) Tagged With: Band 4, smc-6305-10-Longitude and Time Differences, smc-6306-10-Time Differences, syllabus-2027

Measurement, STD2 M2 2023 HSC 7 MC

City `A` is at latitude 34°S and longitude 151°E. City `B` is 72° north of City `A` and 25° west of City `A`.

What are the latitude and longitude of City `B`?

  1. 16°N, 126°E
  2. 16°N, 176°E
  3. 38°N, 126°E
  4. 38°N, 176°E
Show Answers Only

`C`

Show Worked Solution

`text{Latitude of city}\ A: \ -34+72=38°text{N}`

`text{Longitude of city}\ A: \ 151-25=126°text{E}`

`=>C`

Filed Under: M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, smc-6305-20-Earth Coordinates, smc-776-30-Earth Coordinates

Measurement, STD2 M2 2021 HSC 20

City A is in Sweden and is located at (58°N, 16°E). Sydney, in Australia, is located at (33°S, 151°E).

Robert lives in Sydney and needs to give an online presentation to his colleagues in City A starting at 5:00 pm Thursday, local time in Sweden.

What time and day, in Sydney, should Robert start his presentation?

It is given that 15° = 1 hour time difference. Ignore daylight saving.  (3 marks)

Show Answers Only

`text(2 am Friday)`

Show Worked Solution

`text{Angular difference}\ = 151 – 16 = 135°`

Mean mark 52%.

`=>\ text{Time difference}\ = 135/15 = 9\ text(hours)`

`text(Sydney is east of Sweden → ahead)`
 

`text{Presentation time (Sydney)}` `=\ text(5 pm Thurs + 9 hours)`  
  `=\ text(2 am Friday)`  

Filed Under: M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, smc-6305-10-Longitude and Time Differences, smc-776-20-Longitude and Time Differences

Measurement, STD2 M2 2011 HSC 27b

Pontianak has a longitude of 109°E, and Jarvis Island has a longitude of 160°W.

Both places lie on the Equator. 

  1. Calculate the shortest distance between these two places (`d`), to the nearest kilometre, using

     

      `d=theta/360 xx  2pir`  where  `theta=91°`  and  `r=6400` km   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. The position of Rabaul is 4° to the south and 48° to the west of Jarvis Island. What is the latitude and longitude of Rabaul?    (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `10\ 165\ text(km)\ \ \ text{(nearest km)}`
  2. `152^@ text(E)`
Show Worked Solution
i.  `text(Shortest distance)` `= 91/360 xx 2 pi r`
  `= 91/360 xx 2 xx pi xx 6400`
  `= 10\ 164.79…`
  `=10\ 165\ text(km)\ text{(nearest km)}`

 

♦♦ Mean mark 33%
ii. `text(Latitude)`
  `4^@\ text(South of Jarvis Island)`
  `text(S)text(ince Jarvis Island is on equator)`
  `=> text(Latitude is)\ 4^@ text(S)`
   
  `text(Longitude)`
  `text(Jarvis Island is)\ 160^@ text(W)`
  `text(Rubail is)\ 48^@\ text(West of Jarvis Island, or 208° West)`
  `text(which is)\ 28^@\ text{past meridian (180°)}`
`=>\ text(Longitude)` `= (180 -28)^@ text(E)`
  `= 152^@ text(E)`

 
`:.\ text(Position is)\ (4^@text{S}, 152^@text{E})`

Filed Under: M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, Band 5, smc-6305-20-Earth Coordinates, smc-776-30-Earth Coordinates

Measurement, STD2 M2 SM-Bank 3

An aircraft travels at an average speed of  913 km/h. It departs from a town in Kenya  (0°, 38°E)  on Tuesday at 10 pm and flies east to a town in Borneo  (0°, 113°E).

  1. Calculate the distance (`d`), to the nearest kilometre, between the two towns, using

     

    `d=theta/360 xx 2 pi r`  where  `theta = 75^@`  and  `r=6400` km  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. How long will the flight take? (Answer to the nearest hour.)   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. What will be the day and local time in Borneo when the aircraft arrives? (Ignore time zones.)   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `8378\ text(km)`
  2. `9\ text(hours)`
  3. `text(12 midday on Wednesday)`
Show Worked Solution
i.   `text(Angular difference in longitude)`

`= 113 – 38`

`= 75^@`
 

`:.\ text(Distance)` `= 75/360 xx 2 xx pi xx 6400`
  `= 8377.58…`
  `= 8378\ text(km)\ text{(nearest km)}`

 

ii.    `text(Flight time)` `= text(Distance)/text(Speed)`
    `= 8378/913`
    `= 9.176…`
    `= 9\ text(hours)\ text{(nearest hr)}`

 

iii.   `text(Time Difference)` `= 75 xx 4`
    `= 300\ text(minutes)`
    `= 5\ text(hours)`

 
`text(Kenya is further East)`

COMMENT: NESA Nov-19 syllabus updates … use longitude to calculate time differences (1° = 4 mins).

`=>\ text(Kenya is +5 hours)`
 

`:.\ text(Arrival time in Kenya)`

`= text{10 pm (Tues) + 5 hrs + 9 hrs}\ text{(flight)}`

`= 12\ text(midday on Wednesday)`

Filed Under: M2 Working with Time (Y11), M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, smc-1102-20-Longitude and Time Differences, smc-6305-10-Longitude and Time Differences, smc-776-20-Longitude and Time Differences

Measurement, STD2 M2 2017 HSC 27d

Island A and island B are both on the equator. Island B is west of island A. The longitude of island A is 5°E and the angle at the centre of Earth (O), between A and B, is 30°.
 

  1. What is the latitude and longitude of island `B`?  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. What time is it on island `B` when it is 10 am on island `A`?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only

a.   `(0°, 25W)`

b.   `8\ text(am)`

Show Worked Solution
a. `text{Longitude (island}\ B)` `= 5-30`
    `= -25`
    `= 25^@\ text(W)`

 

`:.\ text(Island)\ B\ text{is  (0°, 25°W).}`
 

b.    `text(Time difference) = 30 xx 4 = 120 \ text(mins)\ =2\ text(hours)`

`text(S)text(ince)\ B\ text(is west of)\ A,`

`text(Time on island)\ B` `= 10\ text(am less 2 hours)`
  `= 8\ text(am)`
♦ Mean marks (a) 40% and (b) 45%.

Filed Under: M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 5, smc-6305-10-Longitude and Time Differences, smc-6305-20-Earth Coordinates, smc-776-20-Longitude and Time Differences, smc-776-30-Earth Coordinates

Measurement, STD2 M2 2010 HSC 15 MC

In this diagram of the Earth, `O` represents the centre and `B` lies on both the Equator and the Greenwich Meridan.

What is the latitude and longitude of point A?

  1.    30°N  110°E
  2.    30°N  110°W
  3.    60°N  110°E
  4.    60°N  110°W
Show Answers Only

`A`

Show Worked Solution

 `text(S)text(ince A is)  30^circ\  text(North of the Equator)`

   `=> text(Latitude is)  30^circN`

  `text(S)text(ince A is)  110^circ\  text(East of Greenwich)`

    `=>text(Longitude is)  110^circE`
 

`:. A\ text(is) \ \  30^circN  110^circE`

`=>  A`

Filed Under: M2 Working with Time (Y11), Positions on the Earth's Surface (Std2-2027) Tagged With: Band 4, smc-6305-20-Earth Coordinates, smc-776-30-Earth Coordinates

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