Circle Geometry, SMB-009 In the diagram, \(OB\) meets the chord \(AC\) such that \(AB = BC\). The length of chord \(AC = 24\), and \(OC = 13\). Find the length of \(OB\). (3 marks) --- 6 WORK AREA LINES (style=lined) --- Show Answers Only \(OB=5\) Show Worked Solution \(OB \perp AC\ \ \text{(line through centre that bisects chord)}\) \(BC= \dfrac{1}{2} \times 24 = 12 \) \(\text{Using Pythagoras in}\ \Delta OBC :\) \(OB^2\) \(= 13^2-12^2 \) \(= 25\) \(\therefore OB\) \(=5\)