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Circle Geometry, SMB-014

Find \(\angle ADC\).  (2 marks)   

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\(x= 84^{\circ}\)

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\(\angle ABC = 180-105=75^{\circ}\ \ \text{(straight line)} \)

\(\angle ADC\) \(=180-75\ \ \text{(opposite angles of cyclic quad are supplementary)}\)  
  \(=105^{\circ} \)  

Filed Under: Circle Geometry Tagged With: num-title-ct-path, smc-4240-30-Cyclic quads

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