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Circle Geometry, SMB-018

In the diagram, `AB` is a diameter of a circle with centre `O`. The point `C` is chosen such that `Delta ABC` is acute-angled. The circle intersects `AC` and `BC` at `P` and `Q` respectively.
 

Why is `/_BAC = /_CQP`?   (2 marks)

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`/_BAC + /_BQP = 180°\ \ (APQB\ text{is a cyclic quad})`

`/_CQP + /_BQP = 180°\ text{(}/_ CQB\ text{is a straight line)}`

`:.\ /_BAC = /_CQP`

Filed Under: Circle Geometry Tagged With: num-title-ct-path, smc-4240-30-Cyclic quads

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