Circles, SM-Bank 049

Calculate the total perimeter of the quadrant below, giving your answer correct to one decimal place. (2 marks)

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\(105.3\ \text{km (1 d.p.)}\)

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\(\text{Perimeter}=2\times \text{radius}+\dfrac{\text{circumference}}{4}\)

\(\text{Perimeter}\)	\(=2r+\dfrac{2\pi r}{4}\)
	\(=2\times 29.5+\Bigg(\dfrac{2\pi \times 29.5}{4}\Bigg)\)
	\(=105.3384 \dots\)
	\(=105.3\ \text{km (1 d.p.)}\)