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Compound Interest, SMB-027 MC

An amount of $8000 is invested for a period of 4 years.

The interest rate for this investment is 7.2% per annum compounding quarterly.

The interest earned by the investment in the fourth year (in dollars) is given by

  1. `8000 xx 1.018^4 - 8000 xx 1.018^3`
  2. `8000 xx 1.072^4 - 8000 xx 1.072^3`
  3. `8000 xx 1.018^16 - 8000 xx 1.018^12`
  4. `8000 xx 1.072^16 - 8000 xx 1.072^12`
Show Answers Only

 `C`

Show Worked Solution

`text{Interest earned in 4th year}\ = FV\text{(after 4 years)}-FV\text{(after 3 years)}`

`text{Interest rate}\ (r) = \frac{7.2%}{4} = \frac{0.072}{4} = 0.018`

`text{Compounding periods (3 years)}\ = 3 xx 4 = 12`

`text{Compounding periods (4 years)}\ = 4 xx 4 = 16`
 

`FV\text{(after 4 years)}\ = PV(1+r)^n = 8000(1.018)^16`

`FV\text{(after 3 years)}\ = 8000(1.018)^12`

`:.\ text(Interest earned in 4th year) = 8000 xx 1.018^(16)-8000 xx 1.018^(12)`

`=>  C`

Filed Under: Compound Interest Tagged With: num-title-ct-coreb, smc-4334-45-Find interest earned

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