Equations, SM-Bank 050 Find the value of \(c\) in the formula \(c=\sqrt{a^2+b^2}\) if \(a=12\) and \(b=5\). (2 marks) Show Answers Only \(c=13\) Show Worked Solution \(c\) \(=\sqrt{a^2+b^2}\) \(c\) \(=\sqrt{12^2+5^2}\) \(c\) \(=\sqrt{144+25}\) \(c\) \(=\sqrt{169}\) \(c\) \(=13\)