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Equations, SM-Bank 063

A square has an area of \(36\ \text{m}^2\).

  1. Find the side length of the square.  (2 marks)

  2. Find the perimeter of the square.  (2 marks)

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a.    \(6\ \text{m}\)

b.    \(24\ \text{m}\)

Show Worked Solution
a.    \(A\) \(=s^2\)
  \(A\) \(=36\ \ \text{(given)}\)
  \(\therefore\ s^2\) \(=36\)
  \(\sqrt{s^2}\) \(=\sqrt{36}\)
  \(s\) \(=6\)

 
\(\text{Side length}=6\ \text{m}\)

b.    \(\text{Perimeter}\) \(=4\times s\)
    \(=4\times 6\)
    \(=24\)

 
\(\text{Perimeter}=24\ \text{m}\)