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Equations, SM-Bank 066

Solve the quadratic equation  \(x^2+3=147\)  for  \(x<0\).  (2 marks)

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\(x=-12\)

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\(x^2+3\) \(=147\)
\(x^2\) \(=147-3\)
\(x^2\) \(=144\)
\(\sqrt{x^2}\) \(=\sqrt{144}\)
\(x\) \(=\pm12\)

 
\(\therefore\ \text{Since}\ x<0\ x=-12\)

Filed Under: Equations Tagged With: num-title-ct-core, smc-4215-35-Quadratics

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