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Indices, SMB-030

Find the reciprocal of   `1/a + 1/b -c/(ab)`.   (3 marks)

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`(ab)/(a+b-c)`

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`1/a + 1/b -c/(ab)` `=b/(ab)+a/(ab)-c/(ab)`
  `=(b+a-c)/(ab)`

 
`text(Reciprocal of)\ \ x = x^(-1)`

`:.\ text(Reciprocal of)\ \ (b+a-c)/(ab)=>((b+a-c)/(ab))^(-1)=(ab)/(a+b-c)`

Filed Under: Indices Tagged With: num-title-ct-pathb, smc-4228-52-Reciprocal

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