Complete the table of values below for the given rule. (2 marks)
\( v=4u-3\)
\begin{array} {|l|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ u\ \ \rule[-1ex]{0pt}{0pt} & -2 & -1 &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ v\ \ \rule[-1ex]{0pt}{0pt} & & & & \\
\hline
\end{array}
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