Linear Relationships, SM-Bank 037

Complete the table of values below for the rule \( y=5-x\). (2 marks)

\begin{array} {|l|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} & -1 &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & & & & \\
\hline
\end{array}
Use the table to list the coordinates of the points. (2 marks)

--- 3 WORK AREA LINES (style=lined) ---

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a. \(\text{Table of values}\)

\begin{array} {|l|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt}& -1 &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & 6 & 5 & 4 & 3\\
\hline
\end{array}

b. \((-1 , 6)\ \ (0 , 5)\ \ (1 , 4)\ \ (2 , 3)\)

Show Worked Solution

a. \(\text{Table of values}\)

\begin{array} {|l|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} &\ \ -1\ \ &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & 5-(-1)=6 & 5-0=5 & 5-1=4 & 5-2=3\\
\hline
\end{array}

b. \((-1 , 6)\ \ (0 , 5)\ \ (1 , 4)\ \ (2 , 3)\)