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Linear Relationships, SM-Bank 038

  1. Complete the table of values below for the rule  \( y=4x-7\).  (2 marks)
     
    \begin{array} {|l|c|c|c|c|}
    \hline
    \rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} &  -1  &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
    \hline
    \rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} &   &   &  & \\
    \hline
    \end{array} 
  2. Use the table to list the coordinates of the points.  (2 marks)

Show Answers Only

a.    \(\text{Table of values}\)

\begin{array} {|l|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt}&  -1  &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & -11  & -7 & -3 & 1\\
\hline
\end{array}

b.    \((-1 , -11)\ \ (0 , -7)\ \ (1 , -3)\ \ (2 , 1)\)

Show Worked Solution

a.    \(\text{Table of values}\)

\begin{array} {|l|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} &\ \ -1\ \ &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & 4\times (-1)-7=-11  & 4\times (0)-7=-7 & 4\times 1-7=-3 &4\times 2-7=1\\
\hline
\end{array}

b.    \((-1 , -11)\ \ (0 , -7)\ \ (1 , -3)\ \ (2 , 1)\)