- Plot the points from the table on the number plane below and join the points using a ruler. (2 marks)
\begin{array} {|l|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} &\ \ -2\ \ &\ \ -1\ \ &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & 5 & 4 & 3 & 2 & 1\\
\hline
\end{array}
- What do you notice about the points? (1 mark)
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- Using either the table or the graph, state the rule connecting \(\large x\) and \(\large y\). (1 mark)
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Show Answers Only
a.
b. \(\text{They form a straight line.}\)
c. \(y=3-x\)
Show Worked Solution
a.
b. \(\text{They form a straight line.}\)
c.
\begin{array} {|l|c|c|c|}
\hline
\rule{0pt}{2.5ex}\ \ x\ \ \rule[-1ex]{0pt}{0pt} &\ \ -2\ \ &\ \ -1\ \ &\ \ 0\ \ &\ \ 1\ \ &\ \ 2\ \ \\
\hline
\rule{0pt}{2.5ex} \ \ y\ \ \rule[-1ex]{0pt}{0pt} & 3-(-2)=5 & 3-(-1)=4 & 3-0=3 & 3-1=2 & 3-2=1\\
\hline
\end{array}
\(\therefore\ \text{Rule: }y=3-x\)