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Logarithms, SMB-002

Solve the equation  `log_3(3x + 5) + log_3(2) = 2`,  for `x`.  (2 marks)

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`x =-1/6`

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`text(Simplify using log laws:)`

`log_3(2(3x + 5))` `=2`
`log_3(6x + 10)` `=2`
`6x +10` `=9`
`6x` `= -1`
`x` `=-1/6`

Filed Under: Logarithms Tagged With: num-title-ct-patha, smc-4243-10-Product/Quotient rules

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