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Quadratics and Cubics, SMB-043

Solve for `p` given  `64p^3+125=0.`  (2 marks)

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`p=-5/4`

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`64p^3+125` `=0`
`64p^3` `=-125`
`p^3` `=-125/64`
`p` `=-root3(125/64)`
  `=-(root3(125))/(root3(64))`
  `= -5/4`

Filed Under: Quadratics and Cubics Tagged With: num-title-ct-pathb, smc-4386-50-Cubics

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