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Right-angled Triangles, SM-Bank 001 MC

Henry flies a kite attached to a long string, as shown in the diagram below.
 

The horizontal distance of the kite to Henry’s hand is 8 m.

The vertical distance of the kite above Henry’s hand is 15 m.

The length of the string, in metres, is

  1.  13
  2.  17
  3.  23
  4.  289
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Using Pythagoras}\)

\(s^2\) \(= 8^2 + 15^2\)
  \(= 289\)
\(\therefore\ s\) \(=\sqrt{289}\)
  \(= 17\ \text{metres}\)

  \(\Rightarrow B\)

Filed Under: Right-angled Triangles Tagged With: num-title-ct-core, smc-4218-30-Hypotenuse

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