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Right-angled Triangles, SM-Bank 026

Find the value of the pronumeral in the right-angled triangle below.  (2 marks)

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\(x=24\)

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\(\text{Pythagoras’ Theorem states:  }a^2+b^2=c^2\)

\(\text{Let }a=x ,\ b=7\ \text{and }c=25\)

\(x^2+7^2\) \(=25^2\)
\(x^2+49\) \(=625\)
\(x^2\) \(=625-49\)
\(x^2\) \(=576\)
\(\therefore x\) \(=\sqrt{576}\)
  \(=24\)