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Right-angled Triangles, SM-Bank 027

Find the value of the pronumeral in the right-angled triangle below.  (2 marks)

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\(x=12\)

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\(\text{Pythagoras’ Theorem states:  }a^2+b^2=c^2\)

\(\text{Let }a=x ,\ b=7\ \text{and }c=25\)

\(x^2+9^2\) \(=15^2\)
\(x^2+81\) \(=225\)
\(x^2\) \(=225-81\)
\(x^2\) \(=144\)
\(\therefore x\) \(=\sqrt{144}\)
  \(=12\)