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Right-angled Triangles, SM-Bank 034

Find the value of the pronumeral in the right-angled triangle below.  (2 marks)

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\(x=25\)

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\(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=24,\ b=7\ \text{and }c=x\)

\(\text{Then}\ \ x^2\) \(=24^2+7^2\)
\(x^2\) \(=625\)
\(x\) \(=\sqrt{625}\)
\(x\) \(=25\)