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Right-angled Triangles, SM-Bank 035

Find the value of the pronumeral in the right-angled triangle below.  (2 marks)

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\(c=15\)

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\(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=9,\ \text{and }b=12\)

\(\text{Then}\ \ c^2\) \(=9^2+12^2\)
\(c^2\) \(=225\)
\(c\) \(=\sqrt{225}\)
\(c\) \(=15\)