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Right-angled Triangles, SM-Bank 037

Find the value of the pronumeral in the right-angled triangle below, giving your answer correct to 1 decimal place.  (2 marks)

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\(c\approx 12.5\ (1\ \text{d.p.})\)

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\(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=10.4,\ \text{and }b=6.9\)

\(\text{Then}\ \ c^2\) \(=10.4^2+6.9^2\)
\(c^2\) \(=155.77\)
\(c\) \(=\sqrt{155.77}\)
\(c\) \(=12.480\dots\)
\(c\) \(\approx 12.5\ (1\ \text{d.p.})\)