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Right-angled Triangles, SM-Bank 038

Find the value of the pronumeral in the right-angled triangle below, giving your answer correct to 1 decimal place.  (2 marks)

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\(c\approx 16.2\ (1\ \text{d.p.})\)

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\(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=15.4,\ \text{and }b=5.1\)

\(\text{Then}\ \ c^2\) \(=15.4^2+5.1^2\)
\(c^2\) \(=263.17\)
\(c\) \(=\sqrt{263.17}\)
\(c\) \(=16.222\dots\)
\(c\) \(\approx 16.2\ (1\ \text{d.p.})\)