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Right-angled Triangles, SM-Bank 039

Find the value of the pronumeral in the right-angled triangle below, giving your answer correct to 1 decimal place.  (2 marks)

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\(c\approx 6.5\ (1\ \text{d.p.})\)

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\(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=4.8,\ \text{and }b=4.4\)

\(\text{Then}\ \ c^2\) \(=4.8^2+4.4^2\)
\(c^2\) \(=42.4\)
\(c\) \(=\sqrt{42.4}\)
\(c\) \(=6.511\dots\)
\(c\) \(\approx 6.5\ (1\ \text{d.p.})\)