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Right-angled Triangles, SM-Bank 049

  1. Calculate the length of the hypotenuse in the following right-angled triangle. Give your answer correct to the nearest metre.   (2 marks)
     

  2. Find the perimeter of the triangle.  (1 mark)
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a.    \(7\ \text{m}\)

b.    \(18\ \text{m}\)

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a.    \(\text{Pythagoras’ Theorem states:  }c^2=a^2+b^2\)

\(\text{Let }a=5\ \text{and }b=6\)

\(\text{Then}\ \ c^2\) \(=5^2+6^2\)
\(c^2\) \(=61\)
\(c\) \(=\sqrt{61}\)
\(c\) \(=7.141\dots\approx 7\)

 
\(\text{The hypotenuse is }7\ \text{metres (nearest metre})\)

b.    \(\text{Perimeter}\)

\(=7+5+6\)

\(=18\ \text{m}\)