Use Pythagoras' Theorem to calculate the perimeter of the trapezium below, correct to 1 decimal place. (3 marks)
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\(\text{Find length of sloped side of trapezium.}\)
\(\text{Pythagoras’ Theorem states: }c^2=a^2+b^2\)
\(\text{Let }a=4\ \text{and }b=7)
| \(\text{Then}\ \ c^2\) | \(=4^2+7^2\) |
| \(c^2\) | \(=65\) |
| \(c\) | \(=\sqrt{65}\) |
| \(c\) | \(=8.062\dots\) |
\(\text{Perimeter}\)
\(=6+7+10+8.062\dots\)
\(=31.062\dots\approx 31.1\ \text{mm}\ (1\ \text{d.p.})\)