Use Pythagoras' Theorem to calculate the perimeter of the isosceles triangle below, correct to the nearest centimetre. (3 marks)
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\(\text{Find length of the equal sides of the triangle.}\)
\(\text{Pythagoras’ Theorem states: }c^2=a^2+b^2\)
\(\text{Let }a=5\ \text{and }b=8\)
| \(\text{Then}\ \ c^2\) | \(=5^2+8^2\) |
| \(c^2\) | \(=89\) |
| \(c\) | \(=\sqrt{89}\) |
| \(c\) | \(=9.433\dots\) |
\(\text{Perimeter}\)
\(=2\times 9.433\dots+10\)
\(=28.867\dots\approx 29\ \text{cm}\ (\text{nearest cm})\)