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Measurement, NAP-D3-CA27 SA

Anthony is tiling one wall of a bathroom.

The wall has 2 identical windows as shown in the diagram below.
 

 
What total area does Anthony need to tile?

   square metres
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`12.9\ text(m²)`

Show Worked Solution
`text(Area)` `= (5.3 xx 3) – 2 xx (1 xx 1.5)`
  `= 15.9 – 3`
  `= 12.9\ text(m²)`

Filed Under: Perimeter, Area and Volume, Perimeter, Area and Volume Tagged With: Band 9, smc-3153-30-Area – Composite shapes, smc-3153-70-Tiling, smc-666-30-Area - Composite shapes, smc-666-70-Tiling

Measurement, NAP-D3-NC32 SA

Anthony creates a tile pattern using tiles in the shape of regular hexagons.

The perimeter of each tile is 24 cm.

He arranges them in the following way.
 

 
He keeps adding tiles in the same way until he has a row with a perimeter of 120 cm.

How many tiles are in Anthony's row?

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`7`

Show Worked Solution

`text(Perimeter of:)`

STRATEGY: Each extra tile adds 24 cm but takes away 8 cm from perimeter (net add of 16 cm).
`text(1 tile)` `= 24\ text(cm)`
`text(2 tiles)` `= 24 + 16 = 40\ text(cm)`
`text(3 tiles)` `= 24 + 16 + 16 = 56\ text(cm)`
`vdots`  
`text(7 tiles)` `= 24 + (6 xx 16) = 24 + 96 = 120\ text(cm)`

Filed Under: Perimeter, Area and Volume, Perimeter, Area and Volume Tagged With: Band 10, smc-3153-10-Perimeter, smc-3153-70-Tiling, smc-666-10-Perimeter, smc-666-70-Tiling

Measurement, NAP-C3-CA28 SA

Tom decided to cover a rectangular floor with tiles.

The tiles are twice as wide as they are long.

The floor is  `5 1/2`  tiles wide and  `11 1/2`  tiles long.
 

 
Using this pattern, what is the total number of tiles Tom will use to cover the floor?

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`226.5\ \  text(tiles)` 

Show Worked Solution

`text(Strategy 1:)`

`text(Tiles in bottom row =)\ 11 1/2`

`text(Tiles in top rows)` `=5 xx 23`
  `=115`

 

`:.\ text(Total tiles) = 115 + 11.5 = 126.5`

 

`text(Strategy 2:)` 

`text(Let)\ \ x= text(length of 1 tile)`

`=>\ text(Area of 1 tile)\ = 1 xx 1/2 = 1/2\ text(u²)`

`text{Area of the floor}` `= 5 1/2 xx 11 1/2`
  `=63.25\ text(u²)`

 

`:.\ text(Total tiles )` `=63.25/0.5` 
  `=126.5\ text(tiles)`

Filed Under: Perimeter, Area and Volume, Perimeter, Area and Volume Tagged With: Band 9, smc-3153-20-Area, smc-3153-70-Tiling, smc-666-20-Area, smc-666-70-Tiling

Measurement, NAP-G3-CA30 SA

Sam moves into a new rectangular office that measures  4.5 m × 3 m.

He decides to cover the floor with square carpet tiles.
 

 
How many boxes of carpet tiles does Sam need to order?

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`24\ text(boxes)`

Show Worked Solution

`text(Area of office in the number of tiles)`

`= 4.5/0.25 xx 3/0.25`

`= 18\ text(tiles) xx 12\ text(tiles)`

`= 216\ text(tiles)`

 

`:.\ text(Number of boxes to order)`

`= 216/9`

`= 24\ text(boxes)`

Filed Under: Perimeter, Area and Volume, Perimeter, Area and Volume Tagged With: Band 10, smc-3153-20-Area, smc-3153-70-Tiling, smc-666-20-Area, smc-666-70-Tiling

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