Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=19 ,\ b=23\ \text{and }c=24\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=19^2+23^2\) |
\(=361+529\) | ||
\(=890\) | ||
\(\ne 24^2\) | ||
\(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=7 ,\ b=15\ \text{and }c=17\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=7^2+15^2\) |
\(=49+225\) | ||
\(=274\) | ||
\(\ne 17^2\) | ||
\(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=6 ,\ b=7\ \text{and }c=8\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=6^2+7^2\) |
\(=36+49\) | ||
\(=85\) | ||
\(\ne 8^2\) | ||
\(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=13 ,\ b=84\ \text{and }c=85\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=13^2+84^2\) |
\(=169+7056\) | ||
\(=7225\) | ||
\(=85^2\) | ||
\(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=1.5 ,\ b=2\ \text{and }c=2.5\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=1.5^2+2^2\) |
\(=2.25+4\) | ||
\(=6.25\) | ||
\(=2.5^2\) | ||
\(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=24 ,\ b=7\ \text{and }c=25\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=24^2+7^2\) |
\(=576+49\) | ||
\(=625\) | ||
\(=25^2\) | ||
\(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(7, 8\) and \(11\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(7,\ 8\ \text{and }11\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=7 ,\ b=8\ \text{and }c=11\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=7^2+8^2\) |
\(=49+64\) | ||
\(=113\) | ||
\(\ne 11^2\) | ||
\(\therefore\ \ \) | \(\ne\text{RHS}\) |
\(\therefore\ 7,\ 8\ \text{and }11\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(1.4, 4.8\) and \(5.2\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(1.4,\ 4.8\ \text{and }5.2\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=1.4 ,\ b=4.8\ \text{and }c=5.2\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=1.4^2+4.8^2\) |
\(=1.96+23.04\) | ||
\(=25\) | ||
\(=5^2\ne\text{RHS}\) |
\(\therefore\ 1.4,\ 4.8\ \text{and }5.2\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(36, 48\) and \(63\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(36,\ 48\ \text{and }63\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=36 ,\ b=48\ \text{and }c=63\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=36^2+48^2\) |
\(=1296+2304\) | ||
\(=3600\) | ||
\(=60^2\ne\text{RHS}\) |
\(\therefore\ 36,\ 48\ \text{and }63\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(1.1 ,\ 6\) and \(6.1\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(1.1,\ 6\ \text{and }6.1\ \text{form a Pythagorean triad.}\)
\(\text{Let }a=1.1 ,\ b=6\ \text{and }c=6.1\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=1.1^2+6^2\) |
\(=1.21+36\) | ||
\(=37.21\) | ||
\(=6.1^2=\text{RHS}\) |
\(\therefore\ 1.1,\ 6\ \text{and }6.1\ \text{form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(12 , 35\) and \(37\) form a Pythagorean triad. (2 marks)
\(\text{See worked solution}\)
\(12,\ 35\ \text{and }37\ \text{form a Pythagorean triad.}\)
\(\text{Let }a=12 ,\ b=35\ \text{and }c=37\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=12^2+35^2\) |
\(=144+1225\) | ||
\(=1369\) | ||
\(=37^2=\text{RHS}\) |
\(\therefore\ 12,\ 35\ \text{and }37\ \text{form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(5 , 12\) and \(13\) form a Pythagorean triad. (2 marks)
\(\text{See worked solution}\)
\(\text{Let }a=5 ,\ b=12\ \text{and }c=13\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
\(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=5^2+12^2\) |
\(=25+144\) | ||
\(=169\) | ||
\(=13^2=\text{RHS}\) |
\(\therefore\ 5,\ 12\ \text{and }13\ \text{form a Pythagorean triad.}\)