Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=19 ,\ b=23\ \text{and }c=24\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=19^2+23^2\) |
| \(=361+529\) | ||
| \(=890\) | ||
| \(\ne 24^2\) | ||
| \(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=7 ,\ b=15\ \text{and }c=17\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=7^2+15^2\) |
| \(=49+225\) | ||
| \(=274\) | ||
| \(\ne 17^2\) | ||
| \(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
\(\text{Let }a=6 ,\ b=7\ \text{and }c=8\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=6^2+7^2\) |
| \(=36+49\) | ||
| \(=85\) | ||
| \(\ne 8^2\) | ||
| \(\therefore\ \text{LHS}\) | \(\ne \text{RHS}\) |
\(\therefore\ \text{The triangle is not right-angled as the sides do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=13 ,\ b=84\ \text{and }c=85\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=13^2+84^2\) |
| \(=169+7056\) | ||
| \(=7225\) | ||
| \(=85^2\) | ||
| \(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=1.5 ,\ b=2\ \text{and }c=2.5\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=1.5^2+2^2\) |
| \(=2.25+4\) | ||
| \(=6.25\) | ||
| \(=2.5^2\) | ||
| \(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the triangle below is right-angled. (2 marks)
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\(\text{See worked solution}\)
\(\text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
\(\text{Let }a=24 ,\ b=7\ \text{and }c=25\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=24^2+7^2\) |
| \(=576+49\) | ||
| \(=625\) | ||
| \(=25^2\) | ||
| \(=\text{RHS}\) |
\(\therefore\ \text{The triangle is right-angled as the sides form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(7, 8\) and \(11\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(7,\ 8\ \text{and }11\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=7 ,\ b=8\ \text{and }c=11\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=7^2+8^2\) |
| \(=49+64\) | ||
| \(=113\) | ||
| \(\ne 11^2\) | ||
| \(\therefore\ \ \) | \(\ne\text{RHS}\) |
\(\therefore\ 7,\ 8\ \text{and }11\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(1.4, 4.8\) and \(5.2\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(1.4,\ 4.8\ \text{and }5.2\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=1.4 ,\ b=4.8\ \text{and }c=5.2\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\rightarrow\ \) | \(a^2+b^2\) | \(=1.4^2+4.8^2\) |
| \(=1.96+23.04\) | ||
| \(=25\) | ||
| \(=5^2\ne\text{RHS}\) |
\(\therefore\ 1.4,\ 4.8\ \text{and }5.2\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(36, 48\) and \(63\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(36,\ 48\ \text{and }63\ \text{do not form a Pythagorean triad.}\)
\(\text{Let }a=36 ,\ b=48\ \text{and }c=63\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=36^2+48^2\) |
| \(=1296+2304\) | ||
| \(=3600\) | ||
| \(=60^2\ne\text{RHS}\) |
\(\therefore\ 36,\ 48\ \text{and }63\ \text{do not form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(1.1 ,\ 6\) and \(6.1\) form a Pythagorean triad. (2 marks)
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\(\text{See worked solution}\)
\(1.1,\ 6\ \text{and }6.1\ \text{form a Pythagorean triad.}\)
\(\text{Let }a=1.1 ,\ b=6\ \text{and }c=6.1\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=1.1^2+6^2\) |
| \(=1.21+36\) | ||
| \(=37.21\) | ||
| \(=6.1^2=\text{RHS}\) |
\(\therefore\ 1.1,\ 6\ \text{and }6.1\ \text{form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(12 , 35\) and \(37\) form a Pythagorean triad. (2 marks)
\(\text{See worked solution}\)
\(12,\ 35\ \text{and }37\ \text{form a Pythagorean triad.}\)
\(\text{Let }a=12 ,\ b=35\ \text{and }c=37\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=12^2+35^2\) |
| \(=144+1225\) | ||
| \(=1369\) | ||
| \(=37^2=\text{RHS}\) |
\(\therefore\ 12,\ 35\ \text{and }37\ \text{form a Pythagorean triad.}\)
Use Pythagoras' Theorem to decide if the numbers \(5 , 12\) and \(13\) form a Pythagorean triad. (2 marks)
\(\text{See worked solution}\)
\(\text{Let }a=5 ,\ b=12\ \text{and }c=13\)
\(\text{Pythagoras’ Theorem states: }a^2+b^2=c^2\)
| \(\text{LHS: }\longrightarrow\ \) | \(a^2+b^2\) | \(=5^2+12^2\) |
| \(=25+144\) | ||
| \(=169\) | ||
| \(=13^2=\text{RHS}\) |
\(\therefore\ 5,\ 12\ \text{and }13\ \text{form a Pythagorean triad.}\)