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Ratio, SM-Bank 054

James found a fly that was 8 mm long in real life.

Calculate the scale used in this scale drawing of the fly.  (2 marks)

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\(7\ :\ 1\)

Show Worked Solution
\(\text{Scale}\) \(=\text{Scaled length}\ :\ \text{Actual length}\)
  \(=5.6\ \text{cm}\ :\ 8\ \text{mm}\)
  \(=56\ \text{mm}\ :\ 8\ \text{mm}\)
  \(=7\ :\ 1\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 053

Oliver's bike is 1.68 metres long in real life.

Calculate the scale used in this scale drawing of Oliver's bike.  (2 marks)

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\(1\ :\ 42\)

Show Worked Solution
\(\text{Scale}\) \(=\text{Scaled length}\ :\ \text{Actual length}\)
  \(=4\ \text{cm}\ :\ 1.68\ \text{m}\)
  \(=4\ \text{cm}\ :\ 168\ \text{cm}\)
  \(=1\ :\ 42\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 052

Macton and Brownville are 15 centimetres apart on a map with a scale of \(1:150\ 000\). How far apart, in kilometres, are the two cities in real life?  (2 marks)

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\(22.5\ \text{km}\)

Show Worked Solution

\(\text{Scale factor}=150\ 000\)

\(\text{Actual distance}\) \(=\text{Scaled distance}\times \text{scale factor}\)
  \(=15\times 150\ 000\ \text{cm}\)
  \(=2\ 250\ 000\ \text{cm}\)
  \(=22.5\ \text{km}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 051

Jinderee and Exetroll are 8 centimetres apart on a map with a scale of \(1\ :\ 2000\). How far apart, in kilometres, are the two towns in real life?  (2 marks)

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\(0.16\ \text{km}\)

Show Worked Solution

\(\text{Scale factor}=2000\)

\(\text{Actual distance}\) \(=\text{Scaled distance}\times \text{scale factor}\)
  \(=8\times 2000\ \text{cm}\)
  \(=16\ 000\ \text{cm}\)
  \(=0.16\ \text{km}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 050

Determine the scale factor if a scaled length of 1.6 centimetres represents an actual length of 0.48 kilometres.  (2 marks)

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\(30\ 000\)

Show Worked Solution

\(\text{Scale ratio}=\text{scale length}\ :\ \text{actual length}\)

\(=1.6\ \text{cm}\ :\ 0.48\ \text{km}\)

\(=1.6\ \text{cm}\ :\ 48\ 000\ \text{cm}\)

\(=1\ :30\ 000\)

\(\text{Scale factor}\)

\(=30\ 000\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 049

Determine the scale factor if an actual length of 2 centimetres represents a scaled length of 5 metres.  (2 marks)

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\(\dfrac{1}{250}\)

Show Worked Solution

\(\text{Scale ratio}=\text{scale length}\ :\ \text{actual length}\)

\(=5\ \text{m}\ :\ 2\ \text{cm}\)

\(=500\ \text{cm}\ :\ 2\ \text{cm}\)

\(=500\ :\ 2\)

\(=1\ :\ \dfrac{1}{250}\)

\(\text{Scale factor}\)

\(=\dfrac{1}{250}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 048

Determine the scale factor if an actual length of 0.3 millimetres represents a scaled length of 15 centimetres.  (2 marks)

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\(\dfrac{1}{500}\)

Show Worked Solution

\(\text{Scale ratio}=\text{scale length}\ :\ \text{actual length}\)

\(=15\ \text{cm}\ :\ 0.3\ \text{mm}\)

\(=1500\ \text{mm}\ :\ 3\ \text{mm}\)

\(=500\ :\ 1\)

\(=1\ :\ \dfrac{1}{500}\)

\(\text{Scale factor}\)

\(=\dfrac{1}{500}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 047

Determine the scale factor if an actual length of 2 millimetres represents a scaled length of 2 metres.  (2 marks)

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\(\dfrac{1}{1000}\)

Show Worked Solution

\(\text{Scale ratio}=\text{scale length}\ :\ \text{actual length}\)

\(=2\ \text{m}\ :\ 2\ \text{mm}\)

\(=2000\ \text{mm}\ :\ 2\ \text{mm}\)

\(=1000\ :\ 1\)

\(=1\ :\ \dfrac{1}{1000}\)

\(\text{Scale factor}\)

\(=\dfrac{1}{1000}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 046

Determine the scale factor if a length of 3 centimetres on a map represents an actual length of 2.4 kilometres.  (2 marks)

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\(80\ 000\)

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\(\text{Scale ratio}\)

\(=3\ \text{cm}\ :\ 2.4\ \text{km}\)

\(=3\ \text{cm}\ :\ 240\ 000\ \text{cm}\)

\(=1\ :\ 80\ 000\)

\(\text{Scale factor}\)

\(=80\ 000\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 045

Determine the scale factor if a length of 5 millimetres on a map represents an actual distance of 20 metres.  (2 marks)

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\(4000\)

Show Worked Solution

\(\text{Scale ratio}\)

\(=5\ \text{mm}\ :\ 20\ \text{m}\)

\(=5\ \text{mm}\ :\ 20\ 000\ \text{mm}\)

\(=1\ :\ 4000\)

\(\text{Scale factor}\)

\(=4000\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 044

A model train is built using a scale of \(4:20\ 000\).

For each of these actual lengths, find the scaled length.

  1. \(40\ \text{m}\)  (1 mark)

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  2. \(87\ 450\ \text{cm}\)  (1 mark)

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  3. \(2400\ \text{m}\)  (1 mark)

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a.    \(\text{8 mm or 0.8 cm}\)

b.    \(\text{17.49 cm or 0.1749 m}\)

c.    \(\text{48 cm or 0.48 m}\)

Show Worked Solution

\(\text{Scale}\ \rightarrow\ 4:20\ 000=1:5000\)

a.    \(\text{Scaled length }\) \(\dfrac{40}{5000}\ \text{m}=\dfrac{40\ 000}{5000}\ \text{mm}\)
    \(=\text{8 mm}=\text{0.8 cm}\)

 

b.    \(\text{Scaled length}\) \(=\dfrac{87\ 450}{5000}\ \text{cm} \)
    \(=\text{17.49 cm}=\text{0.1749 m}\)

 

c.    \(\text{Scaled length}\) \(=\dfrac{2400}{5000}\ \text{m}=\dfrac{240\ 000}{5000}\ \text{cm}\)
    \(=\text{48 cm}=\text{0.48 m}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 043

The scale on a map is \(4:20\ 000\).

For each of these scaled distances, find the actual distances in kilometres.

  1. \(2\ \text{cm}\)  (1 mark)

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  2. \(5\ \text{mm}\)  (1 mark)

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  3. \(18.4\ \text{cm}\)  (1 mark)

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a.    \(100\ \text{m or } 0.1\ \text{km}\)

b.    \(40\ \text{m or } 0.04\ \text{km}\)

c.    \(920\ \text{m or } 0.92\ \text{km}\)

Show Worked Solution

\(\text{Scale}=4:20\ 000=1:5000\)

a.    \(\text{Actual Distance}\) \(=2\ \text{cm}\times 5000 \)
    \(= 10\ 000\ \text{cm}\)
    \(=100\ \text{m}=0.1\ \text{km}\)

 

b.    \(\text{Actual Distance}\) \(=8\ \text{mm}\times 5000 \)
    \(=40\ 000\ \text{mm}\)
    \(=40\ \text{m}=0.04\ \text{km}\)

 

c.    \(\text{Actual Distance}\) \(=18.4\ \text{cm}\times 5000 \)
    \(= 92\ 000\ \text{cm}\)
    \(=920\ \text{m}=0.92\ \text{km}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 042

The scale on a map is \(1:10\ 000\).

For each of these scaled distances, find the actual distances in kilometres.

  1. \(3\ \text{cm}\)  (1 mark)

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  2. \(8\ \text{mm}\)  (1 mark)

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  3. \(24.3\ \text{cm}\)  (1 mark)

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a.    \(300\ \text{m or } 0.3\ \text{km}\)

b.    \(80\ \text{m or } 0.08\ \text{km}\)

c.    \(2430\ \text{m or } 2.43\ \text{km}\)

Show Worked Solution
a.    \(\text{Actual Distance}\) \(=3\ \text{cm}\times 10\ 000 \)
    \(= 30\ 000\ \text{cm}\)
    \(=300\ \text{m}=0.3\ \text{km}\)

 

b.    \(\text{Actual Distance}\) \(=8\ \text{mm}\times 10\ 000 \)
    \(= 80\ 000\ \text{mm}\)
    \(=80\ \text{m}=0.08\ \text{km}\)

 

c.    \(\text{Actual Distance}\) \(=24.3\ \text{cm}\times 10\ 000 \)
    \(= 243\ 000\ \text{cm}\)
    \(=2430\ \text{m}\)
    \(=2.43\ \text{km}\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-35-Scale

Ratio, SM-Bank 035 MC

The actual body length of a beetle Brad has caught is 24 mm.

A scale drawing of the beetle is shown below.

What scale is used in the drawing?

  1. \(1 \text{cm represents } 5\ \text{mm}\)
  2. \(1 \text{cm represents } 2\ \text{mm}\)
  3. \(2 \text{cm represents } 1\ \text{mm}\)
  4. \(5 \text{cm represents } 1\ \text{mm}\)
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\(B\)

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\(\text{Scale:}\)

\(12\ \text{cm}: 24\ \text{mm}\) \(=120\ \text{mm}: 24\ \text{mm}=5:1\)

  
\(\text{In the options given, the ratio of}\ 5 : 1\ \text{occurs when}\)

\(\text{10 mm represents 2 mm}\ \textbf{OR}\ \text{when 1 cm represents 2 mm}\)
  

\(\Rightarrow B\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 034 MC

This picture shows a stone vase.
 

 
The picture is 2 cm high. The actual vase is 40 cm high.

What scale is used in the picture?

  1. \(\text{2 cm represents 20 cm}\)
  2. \(\text{4 cm represents 40 cm}\)
  3. \(\text{1 cm represents 2 cm}\)
  4. \(\text{1 cm represents 20 cm}\)
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\(D\)

Show Worked Solution

\(\text{Scale:}\ \ 2\ \text{cm}\ :\ 40\ \text{cm}\)

\(\rightarrow \text{Divide both sides by }2\)

\(\text{Scale:}\ \ 1\ \text{cm}\ :\ 20\ \text{cm}\)

 
\(\Rightarrow D\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 033 MC

Two places are 5.4 cm apart on a map.

On the map 1 cm represents 4 km.

What is the actual distance between the two places?

  1. \(1.08\ \text{km}\)
  2. \(10.8\ \text{km}\)
  3. \(21.6\ \text{km}\)
  4. \(43.4\ \text{km}\)
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\(C\)

Show Worked Solution
\(\text{Actual distance}\) \(=5.4\times 4\)
  \(=21.6\ \text{km}\)

 
\(\Rightarrow C\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

Ratio, SM-Bank 029 MC

A television broadcasting tower is 800 metres high.

A model of the tower is built with a scale of  1 : 4000.

What is the height of the model?

  1. \(5\ \text{cm}\)
  2. \(20\ \text{cm}\)
  3. \(200\ \text{cm}\)
  4. \(320\ \text{cm}\)
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\(B\)

Show Worked Solution
\(\text{Model height}\) \(=\dfrac{800}{4000}\)
  \(= 0.2\ \text{m}\)
  \(= 20\ \text{cm}\)

 
\(\Rightarrow B\)

Filed Under: Ratio Tagged With: num-title-ct-core, smc-4608-20-Word problems ratio, smc-4608-35-Scale

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