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Volume, SM-Bank 166

The cube and cylinder below both have the same volume.
  

  1. Calculate the volume of the cube in cubic centimetres.  (2 marks)

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  2. Calculate the height of the cylinder, \(\large h\), in centimetres. Give your answer correct to 1 decimal place.  (2 marks)

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a.    \(64\ \text{cm}^3\)

b.    \(5.1\ \text{cm (1 d.p.)}\)

Show Worked Solution
 

a.    \(V\) \(=l\times b\times h\)
    \(=4^3\)
    \(=64\)

 
\(\therefore\ \text{The volume of the cube is 64 cm}^3\)
 

b.    \(\text{Diameter = 4 cm}\ \longrightarrow\ \text{Radius = 2 cm}\)

\(V\) \(=\pi r^2h\)
\(64\) \(=\pi\times 2^2\times h\)
\(64\) \(=4\pi h\)
\(\therefore\ h\) \(=\dfrac{64}{4\pi}\)
  \(=5.092\dots\approx 5.1\ \text{(1 d.p.)}\)

 
\(\therefore\ \text{The height of the cylinder is approximately 5.1 cm}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 165

The cylinder and rectangular prism below both have the same volume.
 

  1. Calculate the volume of the cylinder in cubic centimetres, correct to 2 decimal places.  (2 marks)

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  2. Calculate the length of the side labelled \(\large x\), in the rectangular prism. Give your answer correct to 1 decimal place.  (2 marks)

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a.    \(314.16\ \text{cm}^3\ \text{(2 d.p.)}\)

b.    \(9.8\ \text{cm (1 d.p.)}\)

Show Worked Solution
 

a.    \(\text{Diameter = 10 cm }\longrightarrow\ \text{Radius = 5 cm}\)

\(V\) \(=\pi r^2h\)
  \(=\pi\times 5^2\times 4\)
  \(=314.159\dots\)
  \(\approx 314.16\ \text{(2 d.p.)}\)

 
\(\therefore\ \text{The volume of the cylinder is approximately 314.16 cm}^3\)
 

b.    \(V\) \(=l\times b\times h\)
  \(314.16\) \(=8\times x\times 4\)
  \(314.16\) \(=32x\)
  \(\therefore\ x\) \(=\dfrac{314.16}{32}\)
    \(=9.8175\)
    \(\approx 9.8\ \text{(1 d.p.)}\)

 
\(\therefore\ \text{The side labelled }x\ \text{is approximately 9.8 cm in length}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 161

A right cylinder has a height of 100 millimetres and a radius of 1.1 millimetres. Calculate the volume of the cylinder, giving your answer as an exact value in terms of \(\pi\).  (2 marks)

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\(121\large\pi\ \)\(\text{mm}^3\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
  \(=\pi\times 1.1^2\times 100\)
  \(=121\large\pi\)

 
\(\therefore\ \text{The exact volume of the cylinder is }121\large\pi\ \)\(\text{mm}^3\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 160

A right cylinder has a height of 7 metres and a radius of 4 metres. Calculate the volume of the cylinder, giving your answer as an exact value in terms of \(\pi\).  (2 marks)

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\(112\large\pi\ \)\(\text{m}^3\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
  \(=\pi\times 4^2\times 7\)
  \(=112\large\pi\)

 
\(\therefore\ \text{The exact volume of the cylinder is }112\large\pi\ \)\(\text{m}^3\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 159

A right cylinder has a volume of \(11\ 451\) cubic metres. Calculate the radius of the cylinder if the height is 45 metres.

Give your answer to the nearest whole centimetre.  (2 marks)

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\(9\ \text{m}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(11\ 451\) \(=\pi\times r^2\times 45\)
\(11\ 451\) \(=10\pi\times r^2\)
\(r^2\) \(=\dfrac{11\ 451}{45\pi}\)
\(r^2\) \(=80.999\dots\)
\(r\) \(=\sqrt{80.999}=8.999\dots\)
\(r\) \(\approx 9\ \text{m (nearest whole m)}\)

 
\(\therefore\ \text{The radius of the cylinder is approximately 9 m}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 158

A right cylinder has a volume of 22 cubic metres. Calculate the diameter of the cylinder if the height is 7 metres.

Give your answer to the nearest whole metre.  (3 marks)

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\(2\ \text{m}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(22\) \(=\pi\times r^2\times 7\)
\(22\) \(=7\pi\times r^2\)
\(r^2\) \(=\dfrac{22}{7\pi}\)
\(r^2\) \(=1.000\dots\)
\(r\) \(=\sqrt{1.000}=1.000\dots\)
\(r\) \(\approx 1\ \text{m (nearest whole m)}\)

 
\(\therefore\ \text{The diameter of the cylinder is approximately 2 m}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 157

A right cylinder has a volume of 8482.3 cubic millimetres. Calculate the diameter of the cylinder if the height is 12 millimetres.

Give your answer to the nearest whole millimetre.  (3 marks)

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\(30\ \text{mm}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(8482.3\) \(=\pi\times r^2\times 12\)
\(8482.3\) \(=12\pi\times r^2\)
\(r^2\) \(=\dfrac{8482.3}{12\pi}\)
\(r^2\) \(=224.999\dots\)
\(r\) \(=\sqrt{224.999}=14.999\dots\)
\(r\) \(\approx 15\ \text{mm (nearest whole mm)}\)

 
\(\therefore\ \text{The diameter of the cylinder is approximately 30 mm}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 156

A right cylinder has a volume of \(10\ 178.76\) cubic centimetres. Calculate the radius of the cylinder if the height is 10 centimetres.

Give your answer to the nearest whole centimetre.  (2 marks)

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\(18\ \text{cm}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(10\ 178.76\) \(=\pi\times r^2\times 10\)
\(10\ 178.76\) \(=10\pi\times r^2\)
\(r^2\) \(=\dfrac{10\ 178.76}{10\pi}\)
\(r^2\) \(=323.999\dots\)
\(r\) \(=\sqrt{323.9999}=17.999\dots\)
\(r\) \(\approx 18\ \text{cm (nearest whole centimetre)}\)

 
\(\therefore\ \text{The radius of the cylinder is approximately 18 cm}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 155

A right cylinder has a volume of 50.27 cubic millimetres. Calculate the height of the cylinder if the radius is 2 millimetres.

Give your answer to the nearest whole millimetre.  (2 marks)

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\(4\ \text{mm}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(50.27\) \(=\pi\times 2^2\times h\)
\(50.27\) \(=4\pi\times h\)
\(h\) \(=\dfrac{50.27}{4\pi}\)
  \(=4.00\dots\)
  \(\approx 4\ \text{mm (nearest whole millimetre)}\)

 
\(\therefore\ \text{The height of the cylinder is approximately 4 mm}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 154

A right cylinder has a volume of 4021 cubic metres. Calculate the height of the cylinder if the radius is 8 cm.

Give your answer to the nearest whole metre.  (2 marks)

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\(20\ \text{m}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(4021\) \(=\pi\times 8^2\times h\)
\(4021\) \(=64\pi\times h\)
\(h\) \(=\dfrac{4021}{64\pi}\)
  \(=19.998\dots\)
  \(\approx 20\ \text{m (nearest whole metre)}\)

 
\(\therefore\ \text{The height of the cylinder is approximately 20 m}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 153

A right cylinder has a volume of 2827 cubic centimetres. Calculate the height of the cylinder if the radius is 10 cm.

Give your answer to the nearest whole centimetre.  (2 marks)

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\(9\ \text{cm}\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
\(2827\) \(=\pi\times 10^2\times h\)
\(2827\) \(=100\pi\times h\)
\(h\) \(=\dfrac{2827}{100\pi}\)
  \(=8.998\dots\)
  \(\approx 9\ \text{cm (nearest whole centimetre)}\)

 
\(\therefore\ \text{The height of the cylinder is approximately 9 cm}\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 142

Calculate the volume of the cylinder below in cubic metres.  Give your answer correct to 2 decimal places.  (2 marks)
 

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\(508\ 938.01\ \text{m}^3\)

Show Worked Solution

\(\text{diameter =180 m }\rightarrow\text{ radius = 90 m}\)

\(V\) \(=\pi r^2h\)
  \(=\pi\times 90^2\times 20\)
  \(=508\ 938.009\dots\)
  \(\approx 508\ 938.01\ \text{m}^3\ (\text{2 d.p.})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 141

Calculate the volume of the cylinder below in cubic metres.  Give your answer correct to 1 decimal place.  (2 marks)
 

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\(23.5\ \text{m}^3\)

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\(\text{diameter = 2.4 m }\rightarrow\text{ radius = 1.2 m}\)

\(V\) \(=\pi r^2h\)
  \(=\pi\times 1.2^2\times 5.2\)
  \(=23.524\dots\)
  \(\approx 23.5\ \text{m}^3\ (\text{1 d.p.})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 140

Calculate the volume of the cylinder below in cubic centimetres.  Give your answer correct to 2 decimal places.  (2 marks)
 

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\(1.78\ \text{cm}^3\)

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\(\text{diameter = 1.8 cm }\rightarrow\text{ radius = 0.9 cm}\)

\(V\) \(=\pi r^2h\)
  \(=\pi\times 0.9^2\times 0.7\)
  \(=1.781\dots\)
  \(\approx 1.78\ \text{cm}^3\ (\text{2 d.p.})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 139

Calculate the volume of the cylinder below in cubic metres.  Give your answer correct to 2 decimal places.  (2 marks)
 

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\(9424.78\ \text{m}^3\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
  \(=\pi\times 10^2\times 30\)
  \(=9424.777\dots\)
  \(\approx 9424.78\ \text{m}^3\ (\text{2 d.p.})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 138

Calculate the volume of the cylinder below in cubic metres.  Give your answer correct to the nearest cubic metre.  (2 marks)
 

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\(5\ \text{m}^3\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
  \(=\pi\times 0.6^2\times 4\)
  \(=4.523\dots\)
  \(\approx 5\ \text{m}^3\ (\text{nearest cubic metre})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 137

Calculate the volume of the cylinder below in cubic millimetres.  Give your answer correct to one decimal place.  (2 marks)
 

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\(16\ 964.6\ \text{mm}^3\)

Show Worked Solution
\(V\) \(=\pi r^2h\)
  \(=\pi\times 15^2\times 24\)
  \(=16\ 964.600\dots\)
  \(\approx 16\ 964.6\ \text{mm}^3\ (\text{1 d.p.})\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 012

Tennis balls are packaged in cylindrical containers.

Frank purchases a container of tennis balls that holds three standard tennis balls, stacked one on top of the other.

This container has a radius of 3.4 cm and a height of 20.4 cm, as shown in the diagram below.
 

  1. Calculate the volume of the cylinder in cubic centimetres, correct to one decimal place.  (2 marks)

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  2. If one tennis ball has a volume of 164.6 cm³, how much unused volume, in cubic centimetres, surrounds the tennis balls in this container?
    Round your answer to the nearest whole number.  (1 mark)

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a.    \(740.9\ \text{cm}^3\ \text{(to 1 d.p.)}\)

b.    \(247\ \text{cm}^3\ \text{(nearest cm}^3 \text{)}\)

Show Worked Solution
a.    
\(\text{Volume}\) \(=Ah\)
    \(=\pi\times 3.4^2\times 20.4\)
    \(= 740.86\dots\)
    \(=740.9\ \text{cm}^3\ \text{(to 1 d.p.)}\)

 

b.   
\(\text{Unused volume}\) \(=\text{cylinder volume}-\text{volume of balls}\)
    \(= 740.9-3\times 164.6\)
    \(= 247.1\)
    \(=247\ \text{cm}^3\ \text{(nearest cm}^3 text{)}\)

Filed Under: Cylinders, Prisms Tagged With: num-title-ct-core, smc-4981-15-cylinders

Volume, SM-Bank 004 MC

GEOMETRY, FUR1 2008 VCAA 4 MC

The solid cylindrical rod shown above has a volume of 490.87 cm3. The length is 25.15 cm.

The radius (in cm) of the cross-section of the rod, correct to one decimal place, is

  1. \(2.5\)
  2. \(5.0\)
  3. \(6.3\)
  4. \(19.6\)
Show Answers Only

\(A\)

Show Worked Solution

\(V=\pi r^2h\)

\(\text{Where length} =h = 25.15\ \text{cm,}\ V=490.87\ \text{cm}^3\)

\(\therefore\ 490.87\) \(=\pi\times r^2\times 25.15\)
\(r^2\) \(=\dfrac{490.87}{\pi\times 25.15}\)
  \(= 6.2126\dots\)
\(\therefore\ r\) \(= 2.492\dots\ \text{cm}\)
  \(\approx 2.5\ \text{cm (1 d.p.)}\)

 
\(\Rightarrow A\)

Filed Under: Cylinders Tagged With: num-title-ct-core, smc-4981-15-cylinders

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