SmarterEd

Aussie Maths & Science Teachers: Save your time with SmarterEd

  • Login
  • Get Help
  • About

Interpreting Data, SM-Bank 031

Judge recorded 2 hourly temperatures from the Bureau of Meteorology for his home town, for a 24 hour period beginning at midnight.

  1. What was the temperature at 2 a.m.?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. At what time was the minimum temperature for the 24 hour period?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  3. What was the range of temperatures?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  4. Use the graph to estimate the 2 times of the day when the temperature was 18°C?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  5. Use the graph to estimate the temperature at:
    i.    7:00 a.m.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

    ii.   9:30 a.m.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

    iii.  5:00 p.m.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(13 ^{\circ }\text{C}\)

b.    \(6:00\ \text{a.m.}\)

c.    \(16^{\circ }\text{C}\)

d.    \(9:00\ \text{a.m. and }9:30\ \text{p.m.}\)

e.    i.    \(12 ^{\circ }\text{C}\)

ii.   \(20 ^{\circ }\text{C}\)

iii.  \(25 ^{\circ }\text{C}\)

Show Worked Solution

a.    \(13 ^{\circ }\text{C}\)

b.    \(6:00\ \text{a.m.}\)

c.    \(16^{\circ }\text{C}\)

d.    \(9:00\ \text{a.m. and }9:30\ \text{p.m.}\)

e.    i.    \(12 ^{\circ }\text{C}\)

ii.   \(20 ^{\circ }\text{C}\)

iii.  \(25 ^{\circ }\text{C}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 030 MC

The stem-and-leaf plot shows the number of koalas in a wildlife sanctuary each day during two weeks of bush fires.
 


 

On how many days were there at least 30 koalas in the sanctuary?

  1. 2
  2. 3
  3. 6
  4. 14
Show Answers Only

\(C\)

Show Worked Solution

\(\text{The plot shows 6 data points that}\)

\(\text{are 30 or greater.}\)

\(\Rightarrow C\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 029 MC

Students at a high school were surveyed to find whether they did exercise before school.

The graph below shows the results.
 


 

There were 150 17-year-old students at the high school.

How many 17-year-old students responded 'Every Day'?

  1. 14
  2. 30
  3. 38
  4. 45
Show Answers Only

\(D\)

Show Worked Solution

\(\text{30% of 17-year-old responded ‘Every Day’.}\)

\(\therefore\ \text{Number}\) \(=0.3\times 150\)
  \(=45\)

 
\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 028 MC

Gavin measured the temperature every 3 hours from 6:00 am to 3:00 pm.
 

\begin{array} {|l|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \text{Time of the day} \rule[-1ex]{0pt}{0pt} & \text{6:00 am}& \text{9:00 am} & \text{12:00 pm} & \text{3:00 pm} \\
\hline
\rule{0pt}{2.5ex} \text{Temperature (°C)} \rule[-1ex]{0pt}{0pt} & 22&28&32&29 \\
\hline
\end{array}

 

Which graph shows Gavin's results?

A. B. C. D.
Show Answers Only

\(D\)

Show Worked Solution

\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 027

The goals scored by 4 players in a season of water polo were recorded in the graph below.

Will scored 8 goals in the season.

Sam scored 5 goals.

How many more goals did Bilbo score than Ginili?  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

\(7\ \text{more goals}\)

Show Worked Solution

\(\text{Since Will scored 8 goals,}\)

\(= 2\ \text{goals}\)

\(\longrightarrow\ \text{Bilbo scored 10 goals}\)

\(\longrightarrow\ \text{Ginili scored 3 goals}\)

\(\therefore\ \text{Bilbo scored 7 more goals than Ginili.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 026

Matt and Libby planted 50 trees each over 3 weeks.

The bar chart below shows the amount of trees each planted in each week.
 

How many more trees did Libby plant than Matt in Week 2.  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

\(5\)

Show Worked Solution

\(\text{Trees planted by Matt in Week 2}\)

\(= 35-15\)

\(= 20\)
 

\(\text{Trees planted by Libby in Week 2}\)

\(= 45-20\)

\(= 25\)
 

\(\therefore\ \text{Libby planted 5 more trees than Matt in Week 2.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 025 MC

Camilla asked each student in four year 7 classes if they played soccer.

She recorded the results in the graph below. 
 

 
Which class had the highest number of students that played soccer?

  1. Class A
  2. Class B
  3. Class C
  4. Class D
Show Answers Only

\(A\)

Show Worked Solution

\(\text{Consider each option:}\)

\(\text{Class A}: 8+6=14\)

\(\text{Class B}: 10+3=13\)

\(\text{Class C}: 4+9=13\)

\(\text{Class D}: 11+2=13\)

\(\therefore\ \text{Class A has the most soccer players.}\)

\(\Rightarrow A\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 024 MC

The table shows the time (in seconds) some children can run 100 metres.

Which column graph correctly shows the data in the table?

A. B.
C. D.
   
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Considering the vertical scale of each option:}\)
 

\(\Rightarrow C\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 023

32 students are shown 5 colours and they choose their favourite.

The fractions in the graph below show how the students voted.

How many more students voted for green than blue?  (2 marks)

--- 3 WORK AREA LINES (style=lined) ---

Show Answers Only

\(4\)

Show Worked Solution
\(\text{Votes for green}\) \(=\dfrac{1}{4}\times 32\)
  \(=8\)
   
\(\text{Votes for blue}\) \(=\dfrac{1}{8}\times 32\)
  \(=4\)

 

\(\therefore\ \text{4 more students voted for green than blue.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 022 MC

This graph shows the number of men and women that registered to vote before a council election on different days of the week.
  

On which day is the difference between the number of men and women registering closest to 50?

  1. Monday
  2. Tuesday
  3. Wednesday
  4. Friday
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Each interval = 20 people}\)

\(\text{Difference needs to be 2.5 intervals}\)

\(\therefore\ \text{Tuesday is closest}\)

 
\(\Rightarrow B\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 021 MC

Aaron went on holiday and spent his money on accommodation, golf and meals.

He spent $1500 in total and the pie chart below shows how he spent it.
 

 
How much money did Aaron spend on meals on his holiday?

  1. $225
  2. $375
  3. $425
  4. $600
Show Answers Only

\(A\)

Show Worked Solution

\(\text{Percentage spent on accommodation}\)

\(=\dfrac{675}{1500}\times 100\)

\(=45\%\)
 

\(\rightarrow\ \text{Percentage on meals}=100-(40+45)=15\%\)

\(\therefore\ \text{Amount spent on meals}\)

\(=15\%\times 1500\)

\(=$225\)

\(\Rightarrow A\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 020 MC

This graph shows the number of cockatoos in a gum tree at 15 minute intervals over 4 hours.
 

 
At which time were the lowest number of cockatoos in the gum tree?

  1. 3:00
  2. 3:15
  3. 3:45
  4. 4:00
Show Answers Only

\(C\)

Show Worked Solution

\(\text{The lowest data point is one interval before 4:00 pm.}\)

\(\therefore\ \text{The lowest number were in the tree at 3:45 pm.}\)

\(\Rightarrow C\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 019 MC

The graph below shows the number of people in a supermarket at 15-minute intervals during a 4 hour period.
 


 

What time were the greatest amount of people in the supermarket?

  1. 11:15 AM
  2. 12:00 PM
  3. 12:30 PM
  4. 1:45 PM

Show Answers Only

\(B\)

Show Worked Solution

\(\therefore\ \text{The highest data point in the graph is at 12:00 PM}\)
 

\(\Rightarrow B\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 018 MC

A menswear store recorded the number of items it sold in four different categories.

What category makes up 60% of the total number of items sold?
 


 

  1. Hoodies
  2. Shorts
  3. T-shirts
  4. Pants
Show Answers Only

\(D\)

Show Worked Solution

\(\text{Pants represent more than half of the graph.}\)

\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 017

Body mass index (BMI), in kilograms per square metre, was recorded for a sample of 32 men and displayed in the ordered stem plot below.
  

  1. Describe the shape of the distribution.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. Determine the median BMI for this group of men.  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. People with a BMI of 25 or over are considered to be overweight.
  4. What percentage of these men would be considered to be overweight?  (1 mark)

    --- 3 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(\text{Positively skewed}\)

b.    \(24.55\)

c.    \(37.5\%\)

Show Worked Solution

a.   \(\text{The tail is to the right, therefore positively skewed}\)
 

b.   \(32\ \text{data points}\)

\(\text{Median}\) \(=\dfrac{\text{(16th + 17th)}}{2}\)
  \(=\dfrac{ (24.5 + 24.6)}{2}\)
  \(= 24.55\)

 

c.    \(\text{Percentage}\) \(=\dfrac{12}{32}\times 100\)
    \(=37.5\%\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs, smc-5077-25-Mean Median Mode Range

Interpreting Data, SM-Bank 016 MC

A single back-to-back stem-and-leaf plot would be an appropriate graphical tool to investigate the association between a car’s speed, in kilometres per hour, and the

  1. driver’s age, in years. 
  2. car’s colour (white, red, grey, other). 
  3. average distance travelled, in kilometres.
  4. driver’s sex (female, male).
Show Answers Only

\(D\)

Show Worked Solution

\(\text{In a back-to-back stem-and-leaf plot, the numerical }\)

\(\text{speed data has to be plotted against categorical data}\)

\(\text{with two options.}\)

\(\therefore\ \text{Driver’s sex (M or F)}\)

\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 015 MC

The back-to-back ordered stem-and-leaf plot below shows the distribution of maximum temperatures (in °Celsius) of two towns, Beachside and Flattown, over 21 days in January.
 


 

For this distribution, which of the following is not true?

  1. The range of temperatures for Flattown is greater than the range of temperatures for Beachside.
  2. The median temperature for Beachside is lower than the median temperature for Flatttown.
  3. The distribution of temperatures for Beachside is positively skewed.
  4. The maximum temperatures for Flattown are generally lower than those of Beachside.
Show Answers Only

\(D\)

Show Worked Solution

\(\text{Options A}\ \rightarrow\ \text{Flattown Range}=28,\ \ \text{Beachside Range}=23\ \checkmark\)

\(\text{Options B}\ \rightarrow\ \text{Flattown Median}=37,\ \ \text{Beachside Median}=23\ \checkmark\)

\(\text{Options C}\ \rightarrow \ \text{Beachside distribution has a tail to the right, so positively skewed}\ \checkmark\)

\(\text{Options D}\ \rightarrow \ \text{Flattown has 8 max temps that are}\geq\ \text{to those of Beachside.  ×}\)
 

\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs, smc-5077-25-Mean Median Mode Range

Interpreting Data, SM-Bank 014 MC

The stem-and-leaf plot below displays 30 temperatures recorded at a cold climate weather station.
 

The modal temperature is

  1.  2.8°C
  2.  2.9°C
  3.  3.7°C
  4.  8.0°C
Show Answers Only

\(A\)

Show Worked Solution

\(\text{2.8° appears the most in this data set.}\)

\(\Rightarrow A\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 013 MC

The back-to-back ordered stem plot below shows the female and male smoking rates, expressed as a percentage, in 18 countries.
 

  

For these 18 countries, the smoking rates for females are generally

  1. lower and less variable than the smoking rates for males.
  2. lower and more variable than the smoking rates for males.
  3. higher and less variable than the smoking rates for males.
  4. higher and more variable than the smoking rates for males.
Show Answers Only

\(A\)

Show Worked Solution

\(\text{Smoking rates are lower and less variable (range of}\)

\(\text{females rates vs male rates is 13% vs 30%).}\)

\(\Rightarrow A\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 012 MC

The back-to-back ordered stem plot below shows the female and male smoking rates, expressed as a percentage, in 18 countries.
 

  

For these 18 countries, the lowest female smoking rate is

  1. \(5\%\)
  2. \(9\%\)
  3. \(15\%\)
  4. \(19\%\)
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Lowest female smoking rate is 15%.}\)

\(\Rightarrow C\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 011

Table 1 shows the number of rainy days recorded in a high rainfall area for each month during 2022.
 

CORE, FUR2 2009 VCAA 11

 

The dot plot below displays the distribution of the number of rainy days for the 12 months of 2008.
 

CORE, FUR2 2009 VCAA 12
 

  1. Circle the dot on the dot plot that represents the number of rainy days in April 2008.  (1 mark)

    --- 0 WORK AREA LINES (style=lined) ---

  2. For the year 2022, determine

     

i.  the median number of rainy days per month  (1 mark)

--- 2 WORK AREA LINES (style=lined) ---

    1. the percentage of months that have more than 10 rainy days. Write your answer correct to the nearest percent.  (2 marks) 

      --- 3 WORK AREA LINES (style=lined) ---

Show Answers Only

 a.

CORE, FUR2 2009 VCAA 12 Answer

b.    i.    \(15.5\)

ii.    \(92\%\)

Show Worked Solution
a.    CORE, FUR2 2009 VCAA 12 Answer

 

b.i.    \(\text{Median}\) \(=\text{(6th + 7th)}/2\)
    \(=\dfrac{(15+16)}{2}\)
    \(=15.5\)

 

b.ii.   \(\text{Months with more than 10 rainy days}\)

\(=\dfrac{11}{12}\times 100\%\)

\(=91.66\dots\)

\(\approx 92\%\ \text{(nearest %)}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 010 MC

Kerri-anne records the temperature on her verandah at hourly intervals for a 24 hour period.

Which type of graph would best display this data so Kerri-anne could easily see the temperature fluctuations throughout the day?

  1. A sector graph
  2. A stem-and-leaf plot
  3. A column graph
  4. A line graph
Show Answers Only

\(D\)

Show Worked Solution

\(\text{A line graph shows variations over time.}\)

\(\Rightarrow D\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 009 MC

Michael wants to record how he used the data on his phone last week. He spent time on social media, playing games and listening to music.

Which type of graph would best display this data so Michael could easily see the proportion of time spent on each activity?

  1. A sector graph
  2. A stem-and-leaf plot
  3. A column graph
  4. A dot plot
Show Answers Only

\(A\)

Show Worked Solution

\(\text{Sector graph}\)

\(\Rightarrow A\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 008 MC

At the school cross country carnival, the times of the 15 year of girls and boys were recorded.

Which type of graph would best display this data to enable a comparison of the performance of both groups?

  1. A sector graph
  2. Back-to-back stem-and-leaf plot
  3. A column graph
  4. A dot plot
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Back-to-back stem-and-leaf plot}\)

\(\Rightarrow B\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 007 MC

Which type of graph would be best used to show the favourite colours of a group of year 7 students?

  1. A sector graph
  2. Stem-and-Leaf plot
  3. A column graph
  4. A dot plot
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Column graph}\)

\(\Rightarrow C\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 006

Hannah is planning an Australian snowboarding trip this winter and is using the chart below to help decide when she should take her holidays and where she should go.
 

Hannah wishes to compare the 2 resorts using statistical information.

  1. Complete the statistical information in the table below.  (2 marks)
     
    \begin{array} {|l|c|c|}
    \hline
    \rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 1}\ \ \ \ \ \ \  \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 2}\ \ \ \ \ \ \  \\
    \hline
    \rule{0pt}{2.5ex} \textbf{Range of snowfall (cm)} \rule[-1ex]{0pt}{0pt}&  & \\
    \hline
    \rule{0pt}{2.5ex} \textbf{Mean of snowfall (cm)} \rule[-1ex]{0pt}{0pt} &   &  \\
    \hline
    \rule{0pt}{2.5ex} \textbf{Median of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & &  \\
    \hline
    \end{array}

    --- 0 WORK AREA LINES (style=lined) ---

  2. Using your results in the table above (a), which resort should Hannah choose to visit for her snowboarding holiday?
    Justify your answer with at least 1 reference to the table.  (1 mark)

    --- 5 WORK AREA LINES (style=lined) ---

  3. Complete the table below, and use it to decide in which month Hannah should book her snowboarding holiday?
    Justify your answer with at least 1 reference to the table and 1 to the graph.  (3 marks)

    \begin{array} {|l|c|c|}
    \hline
    \rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Mean Snowfall}\ \ \ \ \ \ \    \\
    \hline
    \rule{0pt}{2.5ex} \textbf{June} \rule[-1ex]{0pt}{0pt}& \\
    \hline
    \rule{0pt}{2.5ex} \textbf{July} \rule[-1ex]{0pt}{0pt} &  \\
    \hline
    \rule{0pt}{2.5ex} \textbf{August} \rule[-1ex]{0pt}{0pt} & \\
    \hline
    \rule{0pt}{2.5ex} \textbf{September} \rule[-1ex]{0pt}{0pt} & \\
    \hline
    \end{array}

    --- 5 WORK AREA LINES (style=lined) ---

Show Answers Only

a.

\begin{array} {|l|c|c|}
\hline
\rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 1}\ \ \ \ \ \ \  \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 2}\ \ \ \ \ \ \  \\
\hline
\rule{0pt}{2.5ex} \textbf{Range of snowfall (cm)} \rule[-1ex]{0pt}{0pt} &7 &10\\
\hline
\rule{0pt}{2.5ex} \textbf{Mean of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & 10.5  & 10.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{Median of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & 14 & 13.5 \\
\hline
\end{array}

b.    \(\text{See worked solution}\)

c.  

\begin{array} {|l|c|c|}
\hline
\rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Mean Snowfall}\ \ \ \ \ \ \    \\
\hline
\rule{0pt}{2.5ex} \textbf{June} \rule[-1ex]{0pt}{0pt}& 6.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{July} \rule[-1ex]{0pt}{0pt} & 13.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{August} \rule[-1ex]{0pt}{0pt} & 16\\
\hline
\rule{0pt}{2.5ex} \textbf{September} \rule[-1ex]{0pt}{0pt} & 8\\
\hline
\end{array}

\(\text{See worked solution}\)

Show Worked Solution

a.

\begin{array} {|l|c|c|}
\hline
\rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 1}\ \ \ \ \ \ \  \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Resort 2}\ \ \ \ \ \ \  \\
\hline
\rule{0pt}{2.5ex} \textbf{Range of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & 14-7=7 & 17-7=10\\
\hline
\rule{0pt}{2.5ex} \textbf{Mean of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & \dfrac{6+14+13+9}{4}=10.5  & \dfrac{7+11+17+7}{4}=10.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{Median of snowfall (cm)} \rule[-1ex]{0pt}{0pt} & \dfrac{11+17}{2}=14 & \dfrac{14+13}{2}=13.5 \\
\hline
\end{array}

 

b.    \(\text{The mean snowfall for both resorts is the same.}\)

\(\text{The median snowfall for Resort 2 is higher than Resort 1.}\)

\(\text{The range of snowfall for Resort 2 is higher than Resort 1.}\)

\(\text{Based on these findings Hannah should choose Resort 2.}\)

c.   

\begin{array} {|l|c|c|}
\hline
\rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt} &\ \ \ \ \ \ \  \textbf{Mean Snowfall}\ \ \ \ \ \ \    \\
\hline
\rule{0pt}{2.5ex} \textbf{June} \rule[-1ex]{0pt}{0pt}& \dfrac{6+7}{2}=6.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{July} \rule[-1ex]{0pt}{0pt} & \dfrac{14+13}{2}=13.5 \\
\hline
\rule{0pt}{2.5ex} \textbf{August} \rule[-1ex]{0pt}{0pt} & \dfrac{15+17}{2}=16\\
\hline
\rule{0pt}{2.5ex} \textbf{September} \rule[-1ex]{0pt}{0pt} & \dfrac{9+7}{2}=8\\
\hline
\end{array}

 
\(\text{Based on both the information in the graph and the table above,}\)

\(\text{Hannah should holiday in August.}\)

\(\text{The mean snowfall is highest in this month from the table}\)

\(\text{and, from the graph, Resort 2 has its highest snowfall in August which is 3 cm}\)

\(\text{than Resort 1’s highest in July.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5077-15-Reading graphs, smc-5077-25-Mean Median Mode Range

Interpreting Data, SM-Bank 004

Bonn saved $2400 for his annual holiday.

He has drawn the graph below to represent his weekly holiday spending.

  1. What type of graph has been used to display the information?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. Identify the two variables Bonn has used in this graph?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  3. What is the amount per week that Bonn is expecting to spend on his holiday?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  4. Bonn needs keep $600 for airfares to return home. With this in mind, what is the maximum number of weeks that Bonn can be on holidays?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  5. Briefly describe what happens to the amount of savings as the number of weeks on holiday increases?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(\text{Line graph}\)

b.    \(\text{Weeks on Holidays and Savings}\)

c.    \($300\)

d.    \(6\ \text{weeks}\)

e.    \(\text{As the number of weeks on holiday increases the amount of savings decreases.}\)

Show Worked Solution

a.    \(\text{Line graph}\)

b.    \(\text{Weeks on Holidays and Savings}\)

c.    \(\text{From the graph, the Savings spent per week}= $300\)

d.    \(\text{Maximum weeks on holidays}\)

\(=(2400-600)\ ÷\ 300\)

\(=6\ \text{weeks}\)

e.    \(\text{As the number of weeks on holiday increases the amount of savings decreases.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5076-12-Line Graphs, smc-5077-15-Reading graphs

Interpreting Data, SM-Bank 003

Margaret is preparing a report for her supervisor regarding costs for the recent staff development day.

Below is the graph Margaret prepared summarising the cost of the staff lunch for the day.

  1. What type of graph has been used to display the information?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. Identify the two variables Margaret has used in this graph?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  3. What is the cost of lunch per attendee?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  4. If the total cost for the staff lunch was $85, how many attendees were there?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  5. Briefly describe what happens to the total cost of the staff lunch as the number of attendees increases?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(\text{Line graph}\)

b.    \(\text{Number of Attendees and Cost}\)

c.    \($5\)

d.    \(17\)

e.    \(\text{As the number of attendees increases the cost increases.}\)

Show Worked Solution

a.    \(\text{Line graph}\)

b.    \(\text{Number of Attendees and Cost}\)

c.    \(\text{From the graph, the cost per attendee}= $5\)

d.    \(\text{Number of Attendees}\)

\(=$85\ ÷\ 5\)

\(=17\)

e.    \(\text{As the number of attendees increases the cost increases.}\)

Filed Under: Interpreting Data Tagged With: num-title-ct-core, smc-5076-12-Line Graphs, smc-5077-15-Reading graphs

Copyright © 2014–2025 SmarterEd.com.au · Log in