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Functions, 2ADV F1 EQ-Bank 27

The stopping distance of a car on a certain road, once the brakes are applied, is directly proportional to the square of the speed of the car when the brakes are first applied.

A car travelling at 70 km/h takes 58.8 metres to stop.

How far does it take to stop if it is travelling at 105 km/h?  (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

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`132.3\ text(metres)`

Show Worked Solution

`text(Let)\ \ d\ text(= stopping distance)`

`d \prop s^2\ \ =>\ \ d = ks^2`
 

`text(Find)\ k,`

`58.8` `= k xx 70^2`
`k` `= 58.8/(70^2)= 0.012`

 
`text(Find)\ \ d\ \ text(when)\ \ s = 105:`

`d` `= 0.012 xx 105^2`
  `= 132.3\ text(metres)`

Filed Under: Direct and Inverse Variation (Adv-2027), Further Functions and Relations (Y11) Tagged With: Band 4, smc-6383-10-prop kx^n, smc-6383-50-Stopping Distance, smc-987-60-Proportional

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