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Volume, SM-Bank 053

The prism below has a height of 23 centimetres.

Given its volume is 391 cubic centimetres, calculate the cross-sectional area, \((A)\), of the prism.  (2 marks)
 

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\(17\ \text{cm}^2\)

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\(V=391\ \text{cm}^3\ \text{and }h=23\ \text{cm}\)

\(V\) \(=Ah\)
\(391\) \(=23A\)
\(A\) \(=\dfrac{391}{23}\)
\(A\) \(=17\ \text{cm}^2\)

Filed Under: Cross Sections and Perspectives Tagged With: num-title-ct-core, smc-4979-15-Formula

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