PATTERNS, FUR1 2009 VCAA 3 MC

The first four terms of a geometric sequence are 6400, `t_2` , 8100, – 9112.5

The value of `t_2` is

A. `– 7250`

B. `– 7200`

C. `–1700`

D. `7200`

E. `7250`

Show Answers Only

`B`

Show Worked Solution

`text(GP is )6400, t_2, 8100, –9112.5`

`r`	`=t_2/t_1 = t_3/t_2`
`:. t_2 / 6400`	`= (–9112.5) / 8100`
`t_2`	`= (–9112.5 × 6400) / 8100`
	`= – 7200`

`=> B`