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PATTERNS, FUR1 2010 VCAA 4 MC

The first four terms of a geometric sequence are 

`4, – 8, 16, – 32`

The sum of the first ten terms of this sequence is

A.    `–2048`

B.    `–1364`

C.        `684`

D.      `1367`

E.      `4096`

Show Answers Only

`B`

Show Worked Solution

`4, –8, 16, –32)`

♦ Mean mark 41%.
`text(GP where)\ \ \ a` `= 4`
`r` `=t_(2)/t_(1)= (–8)/4=–2`
`S_n` `=(a(r^n – 1))/(r – 1)`
`:.S_10`  `=[4[(–2)^10 – 1]]/(–2 – 1)`
  `= –1364`

`=> B`

Filed Under: APs and GPs - MC Tagged With: Band 5

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