Algebra, STD2 A1 2024 HSC 1 MC If \(x=-2.531\), what is the value of \(x^2\) rounded to 2 decimal places? \(-6.41\) \(-6.40\) \(6.40\) \(6.41\) Show Answers Only \(D\) Show Worked Solution \( x^2\) \(=(-2.531)^2 \) \(=6.405\ldots \) \(=6.41\) \(\Rightarrow D\) ♦♦ Mean mark 29%! COMMENT: Brain dead calculator usage will cause issues here.