Calculus, 2ADV C1 2023 HSC 7 MC v1 It is given that \(y=f(g(x))\), where \(f(2)=5\), \(f^{′}(2)=3\), \(g(4)=2\) and \(g^{′}(4)=-2\). What is the value of \(y^{′}\) at \(x=4\)? \(-6\) \(-2\) \(3\) \(6\) Show Answers Only \(A\) Show Worked Solution \(y\) \(=f(g(x))\) \(y^{′}\) \(=f^{′}(g(4)) \times g^{′}(4)\) \(=f^{′}(2) \times -2\) \(=3 \times -2\) \(=-6\) \(\Rightarrow A\)