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Algebra, STD2 EQ-Bank 27

A train left Strathfield at 7:18 am and arrived at Central Station at 8:52 am. The distance travelled by the train from Strathfield to Central was 94 km.

What was the average speed of this train, correct to the nearest km/h?   (2 marks)

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\(\text{60 km/h}\)

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\(\text{Journey time}=8:52-7:18=1\ \text{hour}\ 34\ \text{minutes}=94\ \text{minutes}\)

\(\text{Convert to hours:}\)

\(\text{94 minutes} =\dfrac{94}{60}=\dfrac{47}{30}\ \text{hours}\)

\(\text{Using}\ \ d=s \times t\ \ \Rightarrow \ \ s=\dfrac{d}{t}:\)

\(s_{\text{avg}}=\dfrac{94}{\frac{47}{30}}=94\times \dfrac{30}{47}=60\ \text{km/h}\)

Filed Under: Applications: BAC, D=SxT and Medication, Applications: BAC, Medicine and d=s x t Tagged With: Band 4, smc-6235-20-\(d=s\times t\), smc-6509-20-\(d=s \times t\)

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