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Trigonometry, 2ADV EQ-Bank 15

Find \(\theta\), given  \(\sqrt{3}\, \sin \theta=\cos \theta\)  for  \(0^{\circ}<\theta<360^{\circ}\).   (2 marks)

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\(\theta=30^{\circ}, 210^{\circ}\)

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\(\sqrt{3}\, \sin \theta\) \(=\cos \theta\)
\(\sin \theta\) \(=\dfrac{1}{\sqrt{3}} \times \cos \theta\)
\(\tan \theta\) \(=\dfrac{1}{\sqrt{3}}\)

 
\(\text{Base angle}\ = 30^{\circ}\)

\(\text{Since tan is positive in 1st/3rd quadrants:}\)

\(\theta=30^{\circ}, (180+30)^{\circ} = 30^{\circ}, 210^{\circ}\)

Filed Under: Trig Identities and Harder Equations Tagged With: Band 4, smc-6412-10-Solve Equation

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