Trigonometry, 2ADV EQ-Bank 15 Find \(\theta\), given \(\sqrt{3}\, \sin \theta=\cos \theta\) for \(0^{\circ}<\theta<360^{\circ}\). (2 marks) --- 5 WORK AREA LINES (style=lined) --- Show Answers Only \(\theta=30^{\circ}, 210^{\circ}\) Show Worked Solution \(\sqrt{3}\, \sin \theta\) \(=\cos \theta\) \(\sin \theta\) \(=\dfrac{1}{\sqrt{3}} \times \cos \theta\) \(\tan \theta\) \(=\dfrac{1}{\sqrt{3}}\) \(\text{Base angle}\ = 30^{\circ}\) \(\text{Since tan is positive in 1st/3rd quadrants:}\) \(\theta=30^{\circ}, (180+30)^{\circ} = 30^{\circ}, 210^{\circ}\)